N the molecule below, how many atoms could make hydrogen bonds with water? the compound has a ch2, double bond, chc, double bond
, chch2ch2cch2c, double bound, chch2sh backbone, with a cooh group attached to the ninth carbon. in this group one oxygen is attached to carbon by a double bond and another oxygen is attached by a single bond, and the seventh carbon of this backbone is double-bonded to oxygen. the group -ch2op is attached to the 3rd carbon. in this group p is double-bonded to oxygen and single-bonded to two –oh groups.
The structure of said compound is sketched according to guide lines provided in statement and is attached below.
Hydrogen Bond Interactions:
Hydrogen Bond Interactions are those interactions which are formed between a partial positive hydrogen atom bonded directly to most electronegative atom (i.e. F, O and N) of one molecule and the partial negative most electronegative atom of another molecule.
In given structure we are having seven most electronegative oxygen atoms (labelled red) and three partial positive hydrogen atoms (labelled blue) directly attached to most electronegative atom (i.e. oxygen atoms).
Therefore, the oxygen atoms will make hydrogen bonds with water's hydrogen atoms and the partial positive hydrogen atoms will make hydrogen bonds with water's oxygen atoms respectively.
If nitrogen monoxide (NO) is added to 2SO2(g) + O2(g) → 2SO3(g),
it will react with O2 and decrease the reaction rate by lowering the amount of O2. So the answer is C. NO decreases collisions between the SO2 and O2 molecules.