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3 years ago

The surface of water can act like a sort of skin due to a property of liquids called

2 answers:

8 0

Surface tension ..viscosity is the thickness of a liquid, doesn't fit here...condensation and evaporation are processes not properties.

Reika [66]3 years ago

8 0

Answer : The correct option is, surface tension.

Explanation :

Viscosity : It is defined as the resistance of a liquid to flowing.

Condensation : It is a physical process in which a phase of matter converted from gas phase to liquid phase.

Evaporation : It is a process in which a phases changes from liquid phase to gas phase.

Surface tension : It is defined as a force present within the layer of a liquid that causes the layer act as an elastic sheet.

Therefore, the surface of water can act like a sort of skin due to a property of liquids called surface tension.

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kow [346]

Answer:

20.9%

Explanation:

The percentage by mass of solution is given by dividing the mass of solute in grams by the mass of solution in grams then multiplying it by 100%.

% Mass of solution = mass of solute/mass of solution × 100%

= (27.0 g/ 129.0 g) × 100%

= 20.93%

= 20.9%

7 0

2 years ago

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The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera

nevsk [136]

Answer:

The volume of carbon dioxide gas generated 468 mL.

Explanation:

The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

Mass of tablet = 3.45 g

Mass of bicarbonate = $3.45 g\times \frac{32.5}{100}=1.121 mol$

Moles of bicarbonate ion = $\frac{1.121 g/mol}{61 g/mol}=0.01840 mol$

$HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)$

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

$\frac{1}{1}\times 0.01840 mol=0.01840 mol$ of carbon dioxide gas

Moles of carbon dioxide gas n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

$PV=nRT$ (ideal gas equation)

$V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L$

1 L = 1000 mL

0.468 L =0.468 × 1000 mL = 468 mL

The volume of carbon dioxide gas generated 468 mL.

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Solvent - the substance in which a solute dissolves to produce a homogeneous mixture

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Explanation:

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