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2 years ago

How many moles of methane are in 20.32 x 10^16 molecules

Chemistry

1 answer:

Marizza181 [45]2 years ago

7 0

Taking into account the definition of avogadro's number, 3.37×10⁻⁷ moles of methane are 20.32×10¹⁶ molecules.

First of all, you have to know that Avogadro's number indicates the number of particles of a substance (usually atoms or molecules) that are in a mole.

Its value is 6.023×10²³ particles per mole and it applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of methane, then 20.32×10¹⁶ molecules are contained in how many moles of methane?

amount of moles of methane= (20.32×10¹⁶ molecules × 1 mole)÷ 6.023×10²³ atoms

Solving:

<u><em>amount of moles of methane= 3.37×10⁻⁷ moles</em></u>

Finally, 3.37×10⁻⁷ moles of methane are 20.32×10¹⁶ molecules.

Learn more about Avogadro's Number:

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<h3>What is Limiting reagent?</h3>

The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.

How do you identify a limiting reagent?

The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.

Start by writing the balanced chemical equation that describes this reaction

$2Na_{(s)} + Cl_{2 (g)} -- > 2NaCl_{(s)}$

Notice that the reaction consumes 2 moles of sodium metal for every 1 mole of chlorine gas that takes part in the reaction and produces 2 moles of sodium chloride.

now we can see that we have 3 moles of sodium and 3 moles of chlorine, according to question. so, we can say that sodium is the limiting reagent in the given situation.

to learn more about Limiting Reagent go to - brainly.com/question/14222359

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emmasim [6.3K]

<h3>Answer:</h3>

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