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soldi70 [24.7K]
4 years ago
14

(3^3 - 9 )^2 ? How would I simplyify this expression

Mathematics
2 answers:
daser333 [38]4 years ago
8 0

(3^3 - 9 )^2

First do what is inside the parenthesis:

3^3 = 27

Now you have:

(27-9)^2

Subtract:

27-9 = 18

Now you have:

(18)^2

Raise 18 to the second power:

18^2 = 324

NARA [144]4 years ago
7 0

Answer:

The simplest result is 324.

Step-by-step explanation:

Note that 3^3 = 27.  Thus, 9 is a factor of both 3^3 and 9 inside those parentheses.

Then (3^3 - 9 )^2 is the same as [ 9(3-1) ]^2, or

[ 9(2) ]^2, or 81*4 = 324.


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8(y+4)=7y+38 asap pls
Readme [11.4K]
Distribute
remember a(b+c)=ab+ac
8(y+4)=8(y)+8(4)=8y+32


8y+32=7y+38
minus 7y both sides
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8 0
3 years ago
Tavon has a gift card for $165 that loses $4 for each 30-day period it is not used. He has another gift card for $145 that loses
sweet [91]

Answer:

Equation 1 = Equation 2

165 - 4x = 145 - 3.50x

Step-by-step explanation:

Let x represent the number of 30-day periods.

Tavon has a gift card for $165 that loses $4 for each 30-day period it is not used.

Therefore the equation =

$165 -$4 × x

= 165 - 4x.......... Equation 1

He has another gift card for $145 that loses $3.50 for each 30-day period it is not used.

$145 -$3.50 × x

= 145 - 3.50x........... Equation 2

Hence, an equation for the number of 30-day periods until the value of the gift cards will be equal is obtained by equating Equation 1 and Equation 2 together

So, we have

Equation 1 = Equation 2

165 - 4x = 145 - 3.50x

We simplify further:

165 - 145 = -3.50 + 4.0x

20 = 0.5x

x = 20/0.5

x = 40

Therefore, number of each 30-day periods until the value of the gift cards will be equal is 40

3 0
3 years ago
Need help on number 16. A recipe calls for 3 cups of sugar for every 5 cups of flour. If the recipe you make requires 2.5 cups o
levacccp [35]
Um what if you multiply 2.5 x5=12.5 then multiply 16x3=48 and then subtract 12.5 by 48 and you will get 77 cups of sugar srry if it is not the right answer this is not my account this is my fathers im not in collage im in 5th grade . so i hope this helped you

5 0
3 years ago
what is the equation of the quadratic function that passes through the points (0,-1),(1,0),and (2,-3)
Alexus [3.1K]

Answer:

-2x^2 + 3x -1

Step-by-step explanation:

y = ax^2 + bx + c

(0,-1):  

-1 = a(0)^2 + b(0) + c

-1 = 0 + 0 + c

-1 = c

(1,0):

0 = a(1)^2 + b(1) + c

0 = a + b + c

(2,-3):

-3 = a(2)^2 + b(2) + c

-3 = 4a + 2b + c

Replace c with -1

0 = a + b -1

1 = a + b

-3 = 4a + 2b -1

-2 = 4a + 2b

-1 = 2a + b

Solve:

2a + b = -1

-1a - b = -1

a = -2

2a + b = -1

-2a -2b = -2

-b = -3 divide both by -1:  b = 3

a = -2; b = 3; c = -1

y = ax^2 + bx + c or y = -2x^2 +3x -1

6 0
3 years ago
1 1/6 divided by 1/12
Ad libitum [116K]

Answer:

14

Step-by-step explanation:

14/12

7 0
2 years ago
Read 2 more answers
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