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Sindrei [870]
3 years ago
5

Solution 1 contains 3.5g of sodium chloride in 500 mL of water. Solution 2 contains 7.5g of glucose in 300 mL of water. If the a

bove solutions were separated by a membrane permeable to water, but not to the solutes, would osmosis occur, and if so, in which direction would water move?
Chemistry
1 answer:
meriva3 years ago
8 0

Answer:

Answer is Object 2 (which has a density of 1.9 g/cm³).

Explanation;

   When object is floating, the weight of that object is less than the up thrust on it.

   When an object fully submerged and floating, then the weight of that object is equal to the up thrust on it.

   This is known as the Archemide's principle.

   Both up thrust and weight depends on the density. Hence, if the density of the solution is high, then the up thrust also high. If the density high, the the weight of the object also high.

   Hence, to sink the object in water, that object should be denser than water. Hence, answer is object 3 which has a higher density than water.

Explanation:

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A.explain what is meant by term
mrs_skeptik [129]

Answer:

Explanation:

1. Atomic numbers:

Atomic number is the number of protons in an atom. It is one of the most diagonistic and representative number used in identifying an atom. The periodic table of element arranges elements based on this number.

No two elements have the same atomic number.

Protons are positively charged particles in an atom.

  • In a neutral atom, the atomic number is the same as the number electrons since electrical neutrality is attained when the number of protons and electrons are the same.
  • The atomic number determines the position of an atom on the periodic table and it is unique for every atom.

2.

Periodic patterns

These are trends on that can be predicted on the periodic table because they shew regularities down a group or sometimes across the period.

Some of these trends are atomic radius, electronegativity, metallicity, nuclear charge e.t.c

Properties of elements can be predicted using these patterns even before they are discovered.

b.

Physical property shared by Helium, Argon and Neon is that they are all gases. All group 8 elements are called noble or inert gases.

Chemical property of these elements: they are chemically unreactive.

These gases are very stable having complete electronic shell configuration. Every atom on the periodic table tries to attain the state of the noble gases.

C.

Noble Gases/ Inert Gases/ Group O elements

6 0
3 years ago
s) Suppose we now collect hydrogen gas, H2(g), over water at 21◦C in a vessel with total pressure of 743 Torr. If the hydrogen g
Elenna [48]

This is an incomplete question, here is a complete question.

Suppose we now collect hydrogen gas, H₂(g), over water at 21°C in a vessel with total pressure of 743 Torr. If the hydrogen gas is produced by the reaction of aluminum with hydrochloric acid:

2Al(s)+6HCl(aq)\rightarrow 2AlCl_3(aq)+3H_2(g)

what volume of hydrogen gas will be collected if 1.35 g Al(s) reacts with excess HCl(aq)? Express  your answer in liters.

Answer : The volume of hydrogen gas that will be collected is 1.85 L

Explanation :

First we have to calculate the number of moles of aluminium.

Given mass of aluminium = 1.35 g

Molar mass of aluminium = 27 g/mol

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Moles of aluminium}=\frac{1.35g}{27g/mol}=0.05mol

The given chemical reaction is:

2Al(s)+6HCl(aq)\rightarrow 2AlCl_3(aq)+3H_2(g)

As, hydrochloric acid is present in excess. So, it is considered as an excess reagent.

Thus, aluminium is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of hydrogen gas

So, 0.005 moles of aluminium will produce = \frac{3}{2}\times 0.05=0.0750mol of hydrogen gas

Now we have to calculate the mass of helium gas by using ideal gas equation.

PV = nRT

where,

P = Pressure of hydrogen gas = 743 Torr

V = Volume of the helium gas = ?

n = number of moles of hydrogen gas = 0.075 mol

R = Gas constant = 62.364\text{ L Torr }mol^{-1}K^{-1}

T = Temperature of hydrogen gas = 21^oC=[21+273]K=294K

Now put all the given values in above equation, we get:

743Torr\times V=0.075mol\times 62.364\text{ L Torr }mol^{-1}K^{-1}\times 294K\\\\V=1.85L

Hence, the volume of hydrogen gas that will be collected is 1.85 L

8 0
3 years ago
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