True because radioactive contamination results in contact with radioactive substances
The statement "According to Le Châtelier's principle, an increase in temperature will shift the equilibrium position toward the products in an endothermic reaction" is definitely true.
<h3>What is Le Châtelier's principle?</h3>
Le Châtelier's principle may be defined as transformations in the temperature, pressure, volume, or concentration of a system that will lead to observable and conflicting changes in the strategy in order to accomplish a refreshed equilibrium state.
According to Le Châtelier's principle, an increase in temperature generates the equilibrium to move in the direction of the product of the endothermic reaction, and the decrease in the temperature rationales the equilibrium to move in the direction of the product of the exothermic reaction.
Therefore, it is well described above.
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Answer:
158 mL
158 mL of 0.1 M of HCl is required to react completely with 1 g mixture of Na2CO3 and NaHCO3, containing equimolar amounts of both
Explanation:
hope helpez -,-~
btw masoom bachi copied me~
Answer:
5.0
Explanation:
We have a buffer system formed by a weak base (C₅H₅N) and its conjugate acid (C₅H₆N⁺). We can calculate the pOH using the Henderson-Hasselbach's equation.
pOH = pKb + log [acid]/[base]
pOH = -log 1.8 × 10⁻⁹ + log 0.02/0.01
pOH = 9.0
Then, we will calculate the pH.
pH + pOH = 14
pH = 14 - pOH = 14 - 9.0 = 5.0
We find out the molar mass of NH₃.
atomic mass (N)=14 u
atomic mass (H)=1 u
atomic weight (NH₃)=14 u + 3(1u)=17 u
Therefore the molar mass of NH₃ will be: 17 g/mol
Then:
1 mol of water=18 g
2) We know that:
1 mol of any substance=6.022 * 10²³ particles.
3)We calculate the mass of 8.00 *10²² molecules
18 g of water----------------------------6.022*10²³ molecules
x---------------------------------------------8.00*10²² molecules
x=(18 g of water * 8.00*10²² molecules) / 6.022 * 10²³ molecules=2.39 g
Answer: the mass of 8.00 *10²² molecules of NH₃ would be 2.39 g.