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zalisa [80]
2 years ago
14

Given the graph of the exponential function, predict the value of y when x = 4.

Mathematics
2 answers:
anygoal [31]2 years ago
8 0

Answer:

x=4

Step-by-step explanation:

Graph.

tester [92]2 years ago
3 0

The answer is C) 81. (4,81)



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2x²-26x+84 (Factor COMPLETELY)
Nadya [2.5K]

\tt{} {2x}^{2}  - 26x + 84

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\tt{}2 {(x}^{2}  - 6x - 7x + 42)

\tt{}2( x \times (x - 6) - 7(x - 6))

\tt{}2(x - 6) \times (x - 7)

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2 years ago
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sergiy2304 [10]
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6 0
3 years ago
Read 2 more answers
We want to find the zeros of this polynomial:
slava [35]

Answer:

x=-3        x=-1            x=2         x=-2

Step-by-step explanation:

p(x) = (x^2 + 4x + 3)(x^2 – 4)

Set this equal to zero to find the x intercepts

0 = (x^2 + 4x + 3)(x^2 – 4)

Using the zero product property

(x^2 + 4x + 3) =0      (x^2 – 4)  =0

Factor

(x+3)(x+1) =0            (x-2) (x+2)=0

Using the zero product property

x+3 =0  x+1 =0          x-2 =0  x+2 =0

x=-3        x=-1            x=2         x=-2

7 0
2 years ago
Jailed has 60 dimes and 60 nickels
Ivenika [448]

Answer:

75 cents

Step-by-step explanation:

60 dimes is 600 cents or $6, 60 nickels is 300 cents or $3. when we add them together we have $9 and we need 9.75 so we need 75 cents more.

5 0
3 years ago
What are the domain restrictions of the expression g2−7g+10g3−6g2+8g ? Select each correct answer.
Sauron [17]

Answer with Step-by-step explanation:

We are given that an expression

f(g)=\frac{g^2-7g+10}{g^3-6g^2+8g}

We have to find domain restriction of the given function.

f(g)=\frac{(g-5)(g-2)}{g(g-4)(g-2)}

Domain restriction means : It is that value of x when substitute in function then  function will  not defined.

It means it is that values which makes denominator zero.

From given function we can see that

When substitute g=0 then it makes denominator zero.

Hence, the function is not defined at g=0

Substitute g=4

Then, it makes denominator zero.

Hence, function is not defined  at g=4

Substitute g=2

Then,it  makes denominator zero.

Hence, function is not defined  at g=2

Therefore, the function is defined for all values of g except g=0, g=2 and g=4

5 0
3 years ago
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