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Mekhanik [1.2K]

3 years ago

15

A students cost for last summer at her community college was 2800. She spent 560 of that in books. What percent of last semester

s college cost was spent on books?

1 answer:

svetoff [14.1K]3 years ago

3 0

Form the ratio 560/2800 and then mult. the result by 100%:

560

--------- * 100% = 20%

2800

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Fine the equivalent expression 4^-5

Novay_Z [31]

Answer:

1/1024

Step-by-step explanation:

1/(4*4*4*4*4)

1/1024

3 0

3 years ago

The business college computing center wants to determine the proportion of business students who have personal computers (PC's)

Anastasy [175]

Answer:

Option A) reject null hypothesis if z is greater than 1.645

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 250

p = 30% = 0.3

Alpha, α = 0.05

Number of women belonging to union , x = 75

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.3\\H_A: p > 0.3$

This is a one-tailed(right) test.

Rejection Region:

$z_{critical} \text{ at 0.05 level of significance } = 1.645$

So, the rejection region will be

$z > 1.64$

That is we will reject the null hypothesis if the calculated z-statistic is greater than 1.645

Option A) reject null hypothesis if z is greater than 1.645

6 0

3 years ago

Addition fractions 2 5/7+6/7=

kupik [55]

Answer:

The answer is: 3 4/7

Step-by-step explanation:

2 5/7+6/7

=2+11/7

=2+1 4/7

=3 4/7

Hope it helps!

8 0

3 years ago

Which of these equations have no solution? Check all that apply.

Llana [10]

2(x + 2) + 2 = 2(x + 3) + 1
2x + 4 + 2 = 2x + 6 + 1
2x + 6 = 2x + 7 - NO SOLUTION
(subtract 2x from both sides, then 6 = 7 FALSE)

2x + 3(x + 5) = 5(x – 3)
2x + 3x + 15 = 5x - 15
5x + 15 = 5x - 15 - NO SOLUTION

4(x + 3) = x + 12
4x + 12 = x + 12 - ONE SOLUTION

4 – (2x + 5) = (–4x – 2)
4 - 2x - 5 = -4x - 2
-2x - 1 = -4x - 2 - ONE SOLUTION

5(x + 4) – x = 4(x + 5) – 1
5x + 20 - x = 4x + 20 - 1
4x + 20 = 4x + 19 - NO SOLUTION

3 0

3 years ago

Read 2 more answers

X³ by a³ + a³by x³=p x³by a³- a³by ³=q eliminate x

sasho [114]

Answer:

Step-by-step explanation:

$\frac{x^3}{a^3} +\frac{a^3}{x^3} =p\\\frac{x^3}{a^3} -\frac{a^3}{x^3} =q\\adding\\2\frac{x^3}{a^3} =p+q\\\frac{x^3}{a^3} =\frac{p+q}{2} \\substitute~in~first\\\frac{p+q}{2} +\frac{2}{p+q} =p\\\frac{(p+q)^2+4}{2(p+q)} =p\\(p+q)^2+4=2p(p+q)\\p^2+q^2+2pq+4-2p^2-2pq=0\\q^2-p^2+4=0\\q^2=p^2-4$

6 0

2 years ago