Answer:
( 6, -11 )
Step-by-step explanation:
do it on a graph called desmos
For this question you have to solve the equation backwards.
A = 1/2 x (b1 + b2) x h
In order to get rid of the 1/2 (since it's division) multiply each side by 2
now we have: 2A = (b1 + b2) x h
Now do the same to the get rid of the (b1 + b2) (divide each side by it)
2A/(b1 + b2) = h
Yes. If the diagonals of a quadrilateral are perpendicular to each other, then the quadrilateral is always rhombus.
9514 1404 393
Answer:
D
Step-by-step explanation:
Regrouping the factors, we have ...