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3 years ago

the point (4,0) lies on a circle with the center at the orgin. what is the area of the circle to the nearsest hundreth?

Mathematics

1 answer:

kvasek [131]3 years ago

3 0

Answer:

50.27 units²

Step-by-step explanation:²

The standard equation of a circle with center at the origin is x² + y² = r², where r is the radius. Substituting 4 for x and 0 for y yields 4² + 0² = r², so we see immediately that r = 4 units.

The formula for the area of a circle is A = πr².

Here, with r = 4, the area is A = π(4 units)² = 16π units², or

50.27 units² to the nearest hundredth.

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Answer:

Choice B: $y = 2\, (x - 6)^{2} + 5$ .

Step-by-step explanation:

For a parabola with vertex $(h,\, k)$ , the vertex form equation of that parabola in would be:

$\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}$ .

In this question, the vertex is $(6,\, 5)$ , such that $h = 6$ and $k = 5$ . There would exist a constant $a$ such that the equation of this parabola would be:

$y = a\, (x - 6)^{2} + 5$ .

The next step is to find the value of the constant $a$ .

Given that this parabola includes the point $(7,\, 7)$ , $x = 7$ and $y = 7$ would need to satisfy the equation of this parabola, $y = a\, (x - 6)^{2} + 5$ .