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4 years ago

Ray QS bisects PQR. IF PQS= 3X AND RQS=2X÷6 THEN PQR IS?

Mathematics

1 answer:

OleMash [197]4 years ago

6 0

It is given in the question that QS bisects angle PQR .

$m \angle PQS = 3x , m \angle RQS =2x+6$

And since, QS bisects angle PQR, therefore

$[tex]m \angle PQS = m \angle RQS$ [/tex]

Substituting the values of angle PQS and angle RQS, we will get

$3x = 2x+6
\\
3x-2x=6
\\
x = 6$

PQR is twice of angle PQS. Therefore angle PQR is

$m \angle PQR = 2*3*6 = 36 degree$

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