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frosja888 [35]
3 years ago
10

Ray QS bisects PQR. IF PQS= 3X AND RQS=2X÷6 THEN PQR IS?

Mathematics
1 answer:
OleMash [197]3 years ago
6 0

It is given in the question that QS bisects angle PQR .

m \angle PQS = 3x , m \angle RQS =2x+6

And since, QS bisects angle PQR, therefore

[tex]m \angle PQS = m \angle RQS[/tex]

Substituting the values of angle PQS and angle RQS, we will get

3x = 2x+6
\\
3x-2x=6
\\
x = 6

PQR is twice of angle PQS. Therefore angle PQR is

m \angle PQR = 2*3*6 = 36 degree

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