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4 years ago

What sequence has an nth term of a(n)=2n+1

Mathematics

1 answer:

Airida [17]4 years ago

4 0

Answer:

3, 5, 7, 9, 11, ......

Step-by-step explanation:

To obtain the first 5 terms in the sequence substitute n = 1, 2, 3, 4, 5 into the n th term formula, that is

a(1) = 2(1) + 1 = 2 + 1 = 3

a(2) = 2(2) + 1 = 4 + 1 = 5

a(3) = 2(3) + 1 = 6 + 1 = 7

a(4) = 2(4) + 1 = 8 + 1 = 9

a(5) = 2(5) + 1 = 10 + 1 = 11

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3 years ago

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[-5, 4) ∪ (4, ∞)

Step-by-step explanation:

Given functions:

$f(x)=\dfrac{1}{x-3}$

$g(x)=\sqrt{x+5}$

Composite function:

$\begin{aligned}(f\:o\:g)(x)&=f[g(x)]\\ & =\dfrac{1}{\sqrt{x+5}-3} \end{aligned}$

Domain: input values (x-values)

For $(f\:o\:g)(x)$ to be defined:

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