Here’re the two points. Another one is (3,3)
 
        
        
        
Sorry, i wish i could help, but really the only thing i know is that 4 is 2 by 2 so using another equation to try to prove otherwise is irrational in itself 
        
             
        
        
        
Answer:
The fraction is 1/4
Step-by-step explanation:
we know that
The area of an equilateral triangle, using the law of sines is equal to



where 
x is the length side of the triangle
In this problem
Let
b ----> the length side of the regular hexagon
2b ---> the length side of the equilateral triangle
step 1
Find the area of the six triangles
Multiply the area of one triangle by 6
![A=6[x^{2}\frac{\sqrt{3}}{4}]](https://tex.z-dn.net/?f=A%3D6%5Bx%5E%7B2%7D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D)

we have

substitute

step 2
Find the area of the regular hexagon
Remember that, a regular hexagon can be divided into 6 equilateral triangles
so
The area of the regular hexagon is the same that the area of 6 equilateral triangles

we have

substitute

step 3
To find out what fraction of the total area of the six triangles is the area of the hexagon, divide the area of the hexagon by the total area of the six triangles

 
        
             
        
        
        
Answer:
3
Step-by-step explanation:
This is a cube root so think what times what times what is 27? 
3 x 3 x 3 = 27 so the answer is 3
Same problem explained 
https://www.mathsisfun.com/numbers/cube-root.html  < in detail. 
Very helpful website check it out
(It's not a random download link or whatever, look at my profile- i dont do that, its completely safe and legit.) 
 
        
             
        
        
        
The answer is A
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