85-12 = 73 degrees needed
4.186 J/degree Celsius, so
73 degrees * 4.186 J/degree = 305.578 J to raise 1 gram 73 degrees
there are 675 grams, so 305.578 * 675 = 206265.15 J
2.06 x 10^5 J are needed
Answer:
Observe odor, determine pH, determine density, determine boiling point
Explanation:
The correct procedures that would be best to use to determine whether a beaker contains only distilled water would be to observe the odor of the liquid in the beaker, determine the pH of the liquid, determine the density, and then determine the boiling point of the liquid.
<em>Water is generally odorless and has a pH of approximately 7 with a density of 1 kg/m3 and a boiling point of 100 </em>
<em>. If the liquid in the beaker ticks all these conditions, then it can be established to be only distilled water.</em>
Answer:The answer is C melting.
Explanation:
The given question is incomplete. The complete question is:
Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
Answer: The number of moles and the mass of the solute are
and
respectively
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
![Molarity=\frac{n\times 1000}{V_s}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7Bn%5Ctimes%201000%7D%7BV_s%7D)
where,
n = moles of solute
= volume of solution in ml
![3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}](https://tex.z-dn.net/?f=3.8%5Ctimes%2010%5E%7B-5%7DM%3D%5Cfrac%7Bn%5Ctimes%201000%7D%7B100.0%7D)
![n=0.38\times 10^{-5}](https://tex.z-dn.net/?f=n%3D0.38%5Ctimes%2010%5E%7B-5%7D)
n = moles of
= ![\frac{\text {given mass}}{\text {Molar mass}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bgiven%20mass%7D%7D%7B%5Ctext%20%7BMolar%20mass%7D%7D)
![0.38\times 10^{-5}=\frac{x}{49g/mol}](https://tex.z-dn.net/?f=0.38%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7Bx%7D%7B49g%2Fmol%7D)
![x=18.62\times 10^{-5}g](https://tex.z-dn.net/?f=x%3D18.62%5Ctimes%2010%5E%7B-5%7Dg)
Thus the number of moles and the mass of the solute are
and
respectively
Answer:
2 PO₄³⁻(aq) + 3 Mg²⁺(aq) ⇒ Mg₃(PO₄)₂(s)
Explanation:
Let's consider the molecular equation that occurs when aqueous solutions of lithium phosphate and magnesium nitrate are mixed.
2 Li₃PO₄(aq) + 3 Mg(NO₃)₂(aq) ⇒ 6 LiNO₃(aq) + Mg₃(PO₄)₂(s)
The complete ionic equation includes all the ions and insoluble species.
6 Li⁺(aq) + 2 PO₄³⁻(aq) + 3 Mg²⁺(aq) + 6 NO₃⁻(aq) ⇒ 6 Li⁺(aq) + 6 NO₃⁻(aq) + Mg₃(PO₄)₂(s)
The net ionic equation includes only the ions that participate in the reaction and insoluble species.
2 PO₄³⁻(aq) + 3 Mg²⁺(aq) ⇒ Mg₃(PO₄)₂(s)