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nadezda [96]
3 years ago
6

What is the difference between a positively charged ion and a negatively charged ion​

Chemistry
2 answers:
Olenka [21]3 years ago
6 0
One is positive one negative
grin007 [14]3 years ago
4 0

one is positive and one is negative

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Change the coefficients until the reaction is balanced. (also if anyone could help me find the rest of the gizmos I would be ver
Artemon [7]

Answer:

1Na₂S + 1Cd(C₂H₃O₂)₂ →  1CdS + 2NaC₂H₃O

Explanation:

1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 1NaC₂H₃O₂

1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂

(on the reactant side there are two molecules of C₂H₃O₂ and 2 atoms of Na, so in order to balance that we put the coefficient 2 on NAC₂H₃O₂)

So the final product is

1Na₂S + 1Cd(C₂H₃O₂)₂ →  1CdS + 2NaC₂H₃O₂

6 0
2 years ago
Please help I need it
lubasha [3.4K]

Answer : The structure are shown below and the number of stereoisomers are possible in 3,5-dimethylnonane and 3,7-dimethyle-5-ethyldecane are 4 and 8 respectively.

Explanation :

Chiral carbon : It is carbon which is attached to the different types of atoms or molecules.

The number of stereoisomers possible for a compound is related to the number of chiral centers (n) present in it as,

\text{Number of stereoisomers}=2^n

where,

'n' is the number of chiral carbon present in the compound.

The number of chiral carbon present in 3,5-dimethylnonane is, 2 that means n = 2 (carbon-3 and carbon-5)

\text{Number of stereoisomers}=2^n=2^2=4

The number of stereoisomers are possible in 3,5-dimethylnonane is, 4

The number of chiral carbon present in 3,7-dimethyle-5-ethyldecane is, 3 that means n = 3 (carbon-3, carbon-5 and carbon-7)

\text{Number of stereoisomers}=2^n=2^3=8

The number of stereoisomers are possible in 3,7-dimethyle-5-ethyldecane is, 8

4 0
3 years ago
When two substances that cannot dissolve each other are mixed, a
11Alexandr11 [23.1K]

Answer:

The heterogeneous mixture that has very small dispersed particles and stays mixed for a long time is colloid. Because colloid has particles that are small enough to suspended but are as large that they can scatter light.

4 0
3 years ago
Read 2 more answers
What volume of a 6.0% W/V glucose (C6H6O6) solution can be prepared using 185g of glucose?
Nana76 [90]

Volume of solution : = 3083.3 ml = 3.0833 L

<h3>Further explanation</h3>

Given

a 6.0% w/v

185 g of glucose

Required

Volume of solution

Solution

% w/v : the mass of solute in a volume of solution or 1 g solute in 100 ml of solution

Can be formulated :

% w/v = (mass solute(g) : volume solution(ml)) x 100

Mass of solute = mass of glucose = 185 g

The volume of solution :

= 185 g : 0.06

= 3083.3 ml

= 3.0833 L

4 0
2 years ago
Write the chemical formulas and names of the binary acids and oxoacids that contain Group 7A elements. Do the same for elements
vaieri [72.5K]

Answer:

Explanation:

Group 7A elements denote halogens so , binary acids are as follows

HF , HCl , HBr , HI .

Oxoacids are as follows

HOF , HOCl , HOClO, HOClO₂ , HOClO₃ , HOBr , HOBrO₂ ,HOBrO₃ ,

HOI , HOIO₂ , HOIO₃

For other groups

H₂S , H₃O⁺ , HCN, H₂SO₄ , H₂SO₃, HNC,HNO₃, HNO₂,H₂N₂O₂,NH₃,H₂CO₃,HN₃,H

3 0
3 years ago
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