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RoseWind [281]
3 years ago
6

You solved a linear system with two equations and two variables and got the equation -6=-6. How many solutions does the systems

of equations have?
Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer:

The system of equations will have an infinite number of solutions.

Step-by-step explanation:

i) when we arrive at a solution of a linear system with two equations and two

 variables and the solution of the equation does not give the value of any

 variable but rather is in the form of an identity like the one given, that is

 -6 = -6, then we can say that the two equations are exactly the same and

  that the system of equations will have an infinite number of solutions.

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We need to find a polynomial function f(x) with degree 3 and zeros 2 and 2i, such that:

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Since 2i is a zero, -2i is also a zero of this function. Thus, we have:

f(x)=a(x-2)(x-2\imaginaryI)(x+2\imaginaryI)

where a is a constant.

Expanding the expression on the right side, we obtain:

\begin{gathered}  \\ f(x)=a(x-2)\lbrack x²-(2i)²\rbrack \\  \\ f(x)=a(x-2)(x²-4i²),\text{ i^^b2=-1} \\  \\ f(x)=a(x-2)(x²+4) \\  \\ f(x)=a(x³-2x²+4x-8) \end{gathered}

Now, using f(-1) = 30, we obtain:

\begin{gathered} 30=a\lbrack(-1)³-2(-1)²+4(-1)-8\rbrack \\  \\ 30=a(-1-2-4-8) \\  \\ 30=a(-15) \\  \\ a=\frac{30}{-15} \\  \\ a=-2 \end{gathered}

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1 year ago
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Answer:

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Step-by-step explanation:

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