Answer:
4.096 kW
Explanation:
Applying,
P = Fvcos∅................. Equation 1
Where P = Power of the motor, F = Force exerted on the motor, v = Velocity, ∅ = angle.
From the question,
Given: F = 500 N, v = 10 m/s, ∅ = 35°
Substitute these values into equation 1
P = 500×10×cos35°
P = 4095.8 W
P = 4.096 kW
Hence the power rating of the moto in kW is 4.096 kW
This is the speed of all em waves travelling in a vacuum
•wind
•snow
•high tide/low tide
•thunder/lightning storms
"If one increases the force on an object, its acceleration increases too because the push it feels is greater"
We have the 2nd law of Newton that relates the 3 concepts; F=m*a. We have that if the mass of an object increases (put weight in luggage), the accelearation decreases; in fact it is inversely proportional to the mass. Hence if the mass is doubled, acceleration is halved. Accelerations is proportional to force; if one doubles the force, the acceleration doubles too.
Answer:
When an external non-zero net force acts on an object, the object accelerates in the direction of the net force. The magnitude of the acceleration is directly proportional to the magnitude of the net force and inversely proportional to the mass of the object
hope this helps u
