Question

A particle confined to a motion along the x axis moves with a constant acceleration of 2.5m/s2. Its velocity at t=0s is 6m/s. Find its velocity at t=4s.

Answer 1

Answer:

v = 16 m/s

Explanation:

It is given that,

Acceleration of a particle along x -axis is $2.5\ m/s^2$

At t = 0s, its velocity is 6 m/s

We need to find the velocity at t = 4 s

It means that the initial velocity of the particle is 6 m/s

Let v is the velocity at t = 4 s

So,

v = u + at

$v=6+2.5\times 4\\\\v=16\ m/s$

So, the velocity at t = 4 s is 16 m/s.