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3 years ago

A brick is dropped from a height of 31.9 meters

Physics

1 answer:

tia_tia [17]3 years ago

4 0

Explanation:

what is asked give brief explanation about question

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B, do earthworms prefer bright light or darkness!

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2 years ago

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just want to double-check that you understand a practical consequence of the expansion of the universe. Light reaches us from a

Daniel [21]

Answer:

The distance of the light is 9.4608 x 10^25 m

Explanation:

Time taken by the light = 10 billion years = 10 x 10^9 years

speed of light = 3 x 10^8 m/s

speed of light in m/years is = (3 x 10^8)/(60 x 60 x 24 x 365) = 9.4608 x 10^15 m/year

distance = speed x time

therefore, the distance of this light = 10 x 10^9 x 9.461 x 10^15 = 9.4608 x 10^25 m

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3 years ago

A circuit contains an EMF source, a resistor R, a capacitor C, and an open switch in series. The capacitor initially carries zer

Flura [38]

Answer:

t = 1.098*RC

Explanation:

In order to calculate the time that the capacitor takes to reach 2/3 of its maximum charge, you use the following formula for the charge of the capacitor:

$Q=Q_{max}[1-e^{-\frac{t}{RC}}]$ (1)

Qmax: maximum charge capacity of the capacitor

t: time

R: resistor of the circuit

C: capacitance of the circuit

When the capacitor has 2/3 of its maximum charge, you have that

Q=(2/3)Qmax

You replace the previous expression for Q in the equation (1), and use properties of logarithms to solve for t:

$Q=\frac{2}{3}Q_{max}=Q_{max}[1-e^{-\frac{t}{RC}}]\\\\\frac{2}{3}=1-e^{-\frac{t}{RC}}\\\\e^{-\frac{t}{RC}}=\frac{1}{3}\\\\-\frac{t}{RC}=ln(\frac{1}{3})\\\\t=-RCln(\frac{1}{3})=1.098RC$

The charge in the capacitor reaches 2/3 of its maximum charge in a time equal to 1.098RC

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4 years ago

If a dog has the mass of 14.5kg and accelerates at a rate of 8m/sec2 →, If he runs into you what is the force he hits you with?

pashok25 [27]

Answer:

F=ma

m=14.5kg

a=8m/s^2

F=14.5×8

F=116N

Explanation:

PLS MARK BRAINLIEST

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3 years ago

What does the area under a curve of a graph of velocity versus time yield? A. Average acceleration O B. Average velocity OC.Tota

frutty [35]

Answer:

option (D)

Explanation:

If we plot a graph between the velocity of the object and the time taken, the slope of graph gives the value of acceleration of the object and the area under the graph gives the product of velocity and time taken that means it is displacement

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3 years ago

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