Answer:ed44
Step-by-step explanation:
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Answer:
7
Step-by-step explanation:
Answer:
18 inches and 9 inches
Step-by-step explanation:
Given, The base of a triangle is twice of the height.
Area = 81 sq inches
Let, Base (b) = 2x
Height (h) = x
Area of the triangle = \frac{1}{2}bh
\frac{1}{2}bh = 81
or, x^{2} = 8
Base = 2×9 inches = 18 inches
Height = 9 inches
Answer:
step 2
Step-by-step explanation: