<h3>
Answer: B) 2</h3>
=========================================================
Explanation:
Take away the four white small squares on the left side. To balance things out, you have to add 4 black squares to the right side.
Also, take away the two white long rectangles from the right side. To balance this out, you have to add 2 gray long rectangles to the left side.
You should have:
- 5 gray rectangles, and no squares (of any color) on the left side
- 10 black squares, no long rectangles (of any color), on the right side
From here you'll group up the 10 black squares so that you'll have 2 black squares per gray rectangle.
This means the solution is 2.
-------------------------------------
If you're curious about the algebraic way to solve, then you could do this:
3x-4 = -2x+6
3x+2x = 6+4
5x = 10
x = 10/5
x = 2
This method doesn't require us to use the visual model.
Answer:
? = 4.28
Step-by-step explanation:
We know that tan theta = opp side / adjacent side
tan 35 = 3 / ?
Multiply each side by ?
? tan 35 = 3
Divide each side by tan 35
? = 3/tan 35
?= 4.28444402
To the nearest hundredth
? = 4.28
Answer:
C) 15 cm is the best estimate.
Step-by-step explanation:
The exact answer is not there, so 15 is the best estimate.
You can use this equation to help you:
d=C/π
Where d is the diameter.
C is the circumference.
And the last one is Pi.
You know that C = 45, so divide that by Pi (3.14).
45/3.14159 = 14.32
The closest answer is 15.
Hope this helps! Have a great day!
<h2>
Hello!</h2>
The answer is: There is a total of 5.797 gallons pumped during the given period.
<h2>
Why?</h2>
To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)
The given function is:
So, the integral will be:
So, integrating we have:
Performing a change of variable, we have:
Then, substituting, we have:
![\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B9%7D%20%5Cint%5Climits%5E4_0%20%7B%281%20%29%5C%20du-%20%5Cfrac%7B5%7D%7B9%7D%20%5Cint%5Climits%5E4_0%20%7B%28%5Cfrac%7B1%7D%7Bu%20%7D%29%5C%20du%3D%5Cfrac%7B5%7D%7B9%7D%20%28u-lnu%29%2F%5B0%2C4%5D)
Reverting the change of variable, we have:
![\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B9%7D%20%28u-lnu%29%2F%5B0%2C4%5D%3D%5Cfrac%7B5%7D%7B9%7D%28%281%2B3t%29-ln%281%2B3t%29%29%2F%5B0%2C4%5D)
Then, evaluating we have:
![\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B9%7D%28%281%2B3t%29-ln%281%2B3t%29%29%5B0%2C4%5D%3D%28%5Cfrac%7B5%7D%7B9%7D%28%281%2B3%284%29-ln%281%2B3%284%29%29%29-%28%5Cfrac%7B5%7D%7B9%7D%28%281%2B3%280%29-ln%281%2B3%280%29%29%29%3D%5Cfrac%7B5%7D%7B9%7D%2810.435%29-%5Cfrac%7B5%7D%7B9%7D%281%29%3D5.797)
So, there is a total of 5.797 gallons pumped during the given period.
Have a nice day!
16=2/3 times number of students
times both sides by 3
48=2 times number of students
divide both sides by 2
24=number of students
there aer 24 students i the club
