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Nuetrik [128]
3 years ago
12

Give the number of significant figures: 369,132,000 sec

Chemistry
2 answers:
Serggg [28]3 years ago
5 0

Answer : The number of significant figures in 369132000 sec are, six (6).

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures are :

  • Digits from 1 to 9 are always significant and have infinite number of significant figures.
  • All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.
  • All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.
  • All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.
  • All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.
  • All zeroes used solely for spacing the decimal point are not significant. For example : 8000 has one significant figure.

As per question,  

The given number is, 369,132,000

According to the rule, all zeroes used solely for spacing the decimal point are not significant. So, the number of significant figures in 369,132,000 are, 6.

Hence, the number of significant figures in 369132000 sec are, six (6).

Yuliya22 [10]3 years ago
3 0
The number of significant figures in 369,132,000 is 6

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his table gives a record of a marble being rolled along the ground. What was the marble's average speed for this entire trip? 0.
andre [41]

The correct answer is 1.5 m/s

Explanation:

To find the average speed of the movement of a body, for example, the movement of the marble. The first step is to know the total distance traveled and the time of the movement. These two details can be found in the graph presented, in this, the maximum distance (vertical axis) is 15 meters and at this distance, the time is 10 seconds. Now, with this information we can use the formula Average speed = Total distance ÷ Total time.

Average speed = \frac{15 meters}{10 seconds}

Average speed= 1.5 m/s

According to this, the correct answer is 1.5 m/s. Also, meters per second or m/s is the correct unit because the distance is provided in meters (m) and the time is provided in seconds (s).

8 0
3 years ago
Determine the mass in grams of 125 mol of neon
Vesnalui [34]
Molar mass of Neon ( Ne ) = 20.1797 g/mol

m = n * mm

m = 125 * 20.1797

m = 2522.4625 g

hope this helps!

5 0
3 years ago
Calculate number of moles present in 2.3g
Natalija [7]

Explanation:

idk if that's the actual answer but I hope it helps (:

4 0
3 years ago
How many liters of 0.305 M K3PO4 solution are necessary to completely react with 187 mL of 0.0184 M NiCl2 according to the balan
Mashutka [201]

Answer:

6.55 mL of K₃PO₄ are required

Explanation:

We need to propose the reaction, in order to begin:

2K₃PO₄ (aq) + 3NiCl₂(aq) →  Ni₃(PO₄)₂ (s) ↓ + 6KCl (aq)

Molarity = mol/L (Moles of solute that are contained in 1 L of solution.)

M = mol / volume(L).  Let's find out the moles of chloride:

- We first convert the volume from mL to L → 187 mL . 1L / 1000mL = 0.187L

0.0184 M . 0.187L = 0.00344 moles of NiCl₂

Ratio is 3:2. Let's propose this rule of three:

3 moles of chloride react with 2 moles of phosphate

Then, 0.00344 moles of NiCl₂ will react with (0.00344 . 2) /3 = 0.00229 moles of K₃PO₄

M = mol / volume(L) → Volume(L) = mol/M

Volume(L) = 0.00229 mol / 0.350 M = 6.55×10⁻³L

We convert the volume from L to mL → 6.55×10⁻³L . 1000mL /1L = 6.55 mL

5 0
3 years ago
What mass of CaCl2 (in g ) should the chemist use?
solmaris [256]

The mass of the solute required is 250.25 g.

<h3>What is the mass of the solute?</h3>

We know that the number of moles of the solute can be used to obtain the mass of the solute that is  required. We can now try to find the mass of the solute that is required.

Concentration of the solution = 0.350M

Volume of the solution = 6.5 L

Number of moles of the solute = 0.350M *  6.5 L

= 2.275 moles

We now have the mass of the solute as;

2.275 moles  * 110 g/mol

= 250.25 g

Th measured mass of the solute that we would have to use is 250.25 g.

Learn more about solute:brainly.com/question/7932885

#SPJ1

Missing parts;

A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?

3 0
1 year ago
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