PLEASE HELP! Which graph has an absolute max at x=2

Mathematics

1 answer:

Dmitry [639]3 years ago

4 0

Answer:

Step-by-step explanation:

The highest point on the graph for c) is in the first quadrant (where x=2 would be).

If you had an equation, you would be able to find critical points on the function by setting the numerator and denominator equal of f'(x)=0 and solve. You'd have to evaluate f(x) at these critical points and end points to figure that out. This is, if you're in calculus and you would ever need assistance otherwise!

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Find the value of k such that lim-->4 (x^2+x-k)/(x-4) exists

7nadin3 [17]

Answer:

k=20

Step-by-step explanation:

when x approaches 4, the denominator x-4 approaches 0

if the denominator is 0, it means that this is invalid

if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit

so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4

so x^2 + x - k = 0 when x = 4

4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20