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3 years ago

PLEASE HELP! Which graph has an absolute max at x=2

Mathematics

1 answer:

Dmitry [639]3 years ago

4 0

Answer:

Step-by-step explanation:

The highest point on the graph for c) is in the first quadrant (where x=2 would be).

If you had an equation, you would be able to find critical points on the function by setting the numerator and denominator equal of f'(x)=0 and solve. You'd have to evaluate f(x) at these critical points and end points to figure that out. This is, if you're in calculus and you would ever need assistance otherwise!

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What is the range of the relation[(-5,0),(-4,-3),(-3,4),(-1,0),(-4,-1)]

vesna_86 [32]

The range is the set of values that the relation takes for the domain for which it is defined.

Is the set of values of the dependent variable.

In this case, we have the relation [(-5,0),(-4,-3),(-3,4),(-1,0),(-4,-1)].

The dependant variable takes the values: 0, -3, 4, 0 and -1. Some values are repeated.

We put the repeated values only once and sort to write the range.

Then, the range is R = {-3, -1, 0, 4}.

Answer: Range = {-3, -1, 0, 4}

4 0

1 year ago

To solve the system of equations by elimination, what could you multiply each equation by to cancel out the x-variable?A:6x-3y=-

Novay_Z [31]

Answer:

Step-by-step explanation:

You could multiply all of equation A by 1/6 and all of equation b by -1/4 to get

A. x-3/2y=-1/3 and B. x+1/4y=/5/4, then subtract the equations from each other to solve

8 0

3 years ago

Divide R300 000 between Leona and Janet in the ratio 3:2.

ella [17]

Answer:

let the ratio be in x 

a/q. 3x + 2x = 300000

 5x = 300000

x = 300000/5

x= 60000

Leona = 60000*3 = 180000

Janet = 60000*2 = 120000

hope it helps

5 0

3 years ago

Can someone help me with (d)

zysi [14]

Answer:

Step-by-step explanation:

1 to the power of anything is still one

1 * 1 * 1 * 1 = 1

8 0

3 years ago

What is the average rate of change of g over the interval -8<x<-2

Tems11 [23]

Answer:

if i knew the answer i would tell you

Step-by-step explanation:

6 0

3 years ago