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NeTakaya
3 years ago
10

A​ one-way road passes under an overpass in the shape of half an​ ellipse, 20 ft high at the center and 20 ft wide. Assuming a t

ruck is 16 ft​ wide, what is the tallest truck that can pass under the​ overpass?\
Physics
1 answer:
Julli [10]3 years ago
5 0

Answer:

The "tallest truck" that it passes by is 12 ft.

Explanation:

Given that,

The truck passes through "Height of an half ellipse" is 20 ft ("a" is "Major axis").

The truck passes through "Width of an ellipse" is 20 ft ("b" is "Minor axis").

The width of the truck is 16 ft (x).

We need to find the greatest "height of the truck" (y) which enters into an ellipse.

We know that,

Equation of ellipse is \frac {x^2}{b^2}+ \frac {y^2}{a^2}=1

Substitute the given values in the above formula,

\frac {16^2}{20^2}+ \frac {y^2}{20^2}=1

\frac {256}{400}+ \frac {y^2}{400}=1

0.64+ \frac {y^2}{400}=1

\frac {y^2}{400}=1-0.64

\frac {y^2}{400}=0.36

y^2=0.36\times400

y^2=144

y=\sqrt{144}

y = 12

Therefore, The "tallest truck" that it passes by is 12 ft.

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7 0
3 years ago
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A ball is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa
vovangra [49]

Answer:

a) 48.5 ft/s

b) 36.5 ft

c) -80.3 ft/s

Explanation:

a)

The equation of motion of the ball is :

y(t) = -16.1 ft/s^2 * t^2 + Vo*t

Where Vo is the initial velocity

If y(5s) = - 160 ft:

-160 ft = -16.1 ft/s^2 * (5 s)^2 + Vo*(5s)

Solving for Vo

Vo  = (16.1*25- 160) ft / 5s = 48.5 ft/s

b)

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

v(t) = -32.2 ft/s^2 * t + Vo

t = Vo/32.2ft/s^2 = 1.5 s

And now, the highest point which the ball reached is given by:

y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)

y(1.5s) = 36.52 ft

c)

We now need the time at which y(t') = -64 ft

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By means of the quadratic formula, we find that

t' = 4.00498 s ≈ 4 s

And the velocity at t = 4s is:

v(4s) = -32.2 ft/s^2 * 4s +48.5 ft/s = -80.3 ft/s

3 0
3 years ago
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The resultant displacement of the man is 109.77 km in the direction N60°E.

<h3>Displacement</h3>

Displacement is the distance travelled in a specified direction.

To calculate displacement, the straight line from starting point to end point of travel is taken and calculated.

<h3>Resultant displacement of the man </h3>

In the example above, a man walks 95 km, East, then 55 km, north.

The two distances form a right-angled triangle with two sides 95 and 55 units. The hypotenuse gives the resultant displacement, D.

Using Pythagoras rule:

D^2 = 95^2 + 55^2

D^2 = 12050

D = 109.77

Thus, the resultant displacement is 109.77 km

To calculate the direction:

Let the direction be y

y + x = 90°

tan x = 55/95

tanx x = 0.578

x = 30°

Then, y = 90 - 30

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Therefore, the resultant displacement of the man is 109.77 km in the direction N60°E.

Learn more about displacement at: brainly.com/question/321442

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Though melting of tin isn't a chemical change, the same logic is applied here...

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