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3 years ago

What is the difference between a neutral atom and an ion?

Physics

1 answer:

nasty-shy [4]3 years ago

6 0

Answer:here u go

Explanation:

Atoms vs. Ions. Atoms are neutral; they contain the same number of protons as electrons. By definition, an ion is an electrically charged particle produced by either removing electrons from a neutral atom to give a positive ion or adding electrons to a neutral atom to give a negative ion.

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A student is running to catch the campus shuttle bus, which is stopped at the bus stop. The student is runnign at a constant spe

Serggg [28]

Answer:

Part a)

$t = 16.8 s$

$d = 100.8 m$

Part b)

$v_f = 2.86 m/s$

Explanation:

Part a)

Constant speed by which the student will run is given as

$v = 5 m/s$

now after some time if student is going to overtake the position of bus

so here the final positions will be same

so we have

$x_{bus} = x_{student}$

$0 + \frac{1}{2}at^2 + d = v_{student} t$

$\frac{1}{2}(0.170)t^2 + 60 = 5 t$

$0.085 t^2 - 5t + 60 = 0$

so it is

$t = 16.8 s$

So student will run the total distance

$d = vt$

$d = (6)(16.8)$

$d = 100.8 m$

Part b)

Speed of bus when student reach the bus is given as

$v_f = v_i + at$

$v_f = 0 + (0.170)(16.8)$

$v_f = 2.86 m/s$

4 0

3 years ago

The total yearly world consumption of energy is approximately 4.0 Ã— 1020 J. How much mass would have to be completely converted

BabaBlast [244]

Answer:

m = 4.4 × 10³ kg

Explanation:

Given that:

The total yearly energy is 4.0 × 10²⁰ J

The amount of mass that provides this energy can be determined by using the formula:

E = mc²

where;

c = speed of light in free space = (3 × 10⁸)

4.0 × 10²⁰ = m × (3 × 10⁸)²

$m = \dfrac{4.0 \times 10^{20} }{(3\times 10^8)^2}$

m = 4.4 × 10³ kg

6 0

3 years ago

A mass is attached to a spring with an unknown spring constant. The spring gains 10 J of elastic potential energy if stretched b

Firlakuza [10]

From the given information in the question, the correct option is Option 1: 14 cm.

A non-stretched elastic spring has a conserved potential energy which gives it the ability to perform work. The elastic potential energy can be expressed as:

PE = $\frac{1}{2}$ k $x^{2}$