G=mg=>m=G/g=16680/9.8=1702 kg
p=mv=>v=p/m=54400/1702=32 m/s
Answer:
Vf = 75.4 m/s
Explanation:
In order to find the final velocity of the penny when it would hit the ground, we will use the equation of motion. In this particular case the third equation of motion can be used. The third equation of motion is written as follows:
2gh = Vf² - Vi²
where,
Vf = Final Velocity of the penny when it would hit the ground = ?
Vi = Initial Velocity of the penny = 0 m/s (Since, the penny starts from rest)
g = acceleration due to gravity = 9.8 m/s²
h = height of building = 290 m
Therefore,
2(9.8 m/s²)(290 m) = Vf² - (0 m/s)²
Vf = √(5684 m²/s²)
<u>Vf = 75.4 m/s</u>
Answer:
Explanation:
The work increased the potential energy
W = PE = mgh = 40(9.8)(15) = 5880 J(oules)
