Answer:
D). energy resulting from the attraction between two masses.
Explanation:
Answer:
<h2>154.73N</h2>
Explanation:
The question is incomplete. Here is the complete question.
Using the strap at an angle of 31° above the horizontal, a Grade 12 Physics student, tired from studying, is dragging his 15 kg school bag across the floor at a constant velocity. (a) If the force of tension in the strap is 51 N, what is the normal force.
Check the diagram related to the question in the attachment below for better understanding.
The normal force is the reaction acting perpendicular to the force of tension in the strap and opposite the weight of the bag. They are the forces acting along the vertical.
The normal force N will be the sum of the force of tension acting along the vertical (Ty) and the weight of the bag (W).
Ty = 15sin31°
Ty = 7.73N
W = mass * acceleration due to gravity
W = 15.0*9.8
W = 147N
The normal force is therefore expressed as;
N = Ty + W
N = 7.73 + 147
N = 154.73N
Answer:
The vehicle displacement is 9.90 feet.
Explanation:
Given that,
Height of tree = 4.5 feet
Distance = 33 feet
According to figure,
We need to calculate the value of l
Using Pythagorean theorem

We need to calculate the vehicle displacement
Using horizontal component
Vehicle displacement =horizontal component of pulled rope

Where,
is angle between rope and ground
d = pulled length of rope


Hence, The vehicle displacement is 9.90 feet.
When solar radiation reaches the Earth it quickly dissipates as most of the radiation and UV rays are blocked by ozone layer, but more radiation and UV rays are able to get through because of global warming.
The fluid that is being passed through the syringe and needle is incompressible, which means that it will transmit pressure equally. Therefore, the pressure on the plunger will be equivalent to the pressure on the needle. We also know that:
Pressure = Force / Area
Pressure on plunger = 4 / (π*(0.012/2)²)
Pressure on plunger = 35.4 kPa
Pressure on needle = 35.4 kPa
35.4 kPa = F / (4 / (π*(0.0025/2)²)
F = 0.17 N
The force on the needle is 0.17 N