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3 years ago

6

A plumber charges $25 for a service call plus $50 per hour of service. Write an equation in slope-intercept form for the cost, C

, after h hours of service. What will be the total cost for 8 hours of work? 10 hours of work?

1 answer:

Alex787 [66]3 years ago

4 0

C= 25$ + 50$ * h

8 hours 425$

10 hours 525$

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Volgvan

Answer:

43

Step-by-step explanation:

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3 years ago

The inequality x < 9 or x ≥ 14 can be used to represent the hourly wage, x, of each employee at a store. Which are possible v

Elodia [21]

Answer:

$11, $13, $14

Step-by-step explanation:

all of those answers are greater than $9 but less than or equal to $14.

7 0

3 years ago

An artist makes a cube-shaped sculpture.

ratelena [41]

All the sides of a cube are always the same.
Area = 12 in x 12 in = 144 in^2
Volume = 12 in x 12 in x 12 in = 1728 in^3

Hence, you can confirm all the side of this cube is 12 in.

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3 years ago

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

or

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

or

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

3 years ago

Two skills needed to become a good performer are determination and hard work

skelet666 [1.2K]

Answer:

True

Step-by-step explanation:

In my opinion the following statement would be true. In order to become good at anything you need to practice, (also could mean hard work) and determination the drive to get good at the act you are working on. Some believe discipline would often be a good way to get good at something.

Hope this helps.

7 0

3 years ago

Read 2 more answers