Answer:
Point form-
(3,-2)
Equation Form:
x=3, y=-2
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Tip: you can use M athway and S ymbolab to help you :)
*easy way to get answers fast
also follow me >>> anni._.perdue
thnxs
mark me brainliest plzz
10 pens=£6.50
1 pen=£0.65
4 pens=£0.65×4
4 pens=£2.6
Answer:
cos3x+tan3x=0
⟹cos3x=−tan3x
⟹cos3x=−sin3xcos3x
⟹cos23x=−sin3x
⟹1−sin23x=−sin3x
⟹sin23x−sin3x−1=0
This is a quadratic equation in sin3x.
sin3x=−(−1)±(−1)2−4×1×(−1)−−−−−−−−−−−−−−−−−√2×1
sin3x=1±5–√2
If x takes real values, the upper sign must be rejected.
sin3x=1−5–√2
⟹3x=nπ+(−1)nsin−11−5–√2
⟹x=13[nπ+(−1)nsin−11−5–√2]
Step-by-step explanation:
Hope this kind of helps
Answer:
A rhombus and a square since a square is also a rhombus.
