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lbvjy [14]
4 years ago
15

How many moles are in 3.01*10^23 atoms of Mg

Chemistry
1 answer:
Basile [38]4 years ago
7 0
1 mole ------------ 6.02x10²³ atoms
? moles ----------- 3.01x10²³ atoms

moles = ( 3.01x10²³ ) x 1 / 6.02x10²³

=> 0.5 moles Mg
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alisha [4.7K]

Answer: By understanding conversion factors and how they are related to each other

Explanation:

Dimensional Analysis is a step by step approach to solving problems in Physics, Chemistry , and Mathematics. It involves having a clear knowledge and understanding to be able to convert a given unit to another in the same dimension using  conversion factors and knowing how they are related to each other.

For instance, In Chemistry, we want to Convert 120mL to L.(note that ml stands for millilitres and ;L stands for litres)

Or first approach will be to write out the conversion factor related to our problem which is

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7 0
3 years ago
what is the percent by mass of NaHCO3 in a solution containing 20.0 g of NaHCO3 dissolved in 600.0 ml of water
Ne4ueva [31]
%(NaHCO3)= ((mass NaHCO3)/(mass NaHCO3 + mass water))*100%

m=Volume*Density
Density of water =1 g/ml
m(water) = Volume(water)*Density(water) = 600.0 ml * 1g/ml=600g water

%(NaHCO3)= ((20.0 g)/(20.0 g + 600 g))*100%=0.0323*100%=32.3%
7 0
4 years ago
A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.
GaryK [48]

Answer:

Kc = 50.5

Explanation:

We determine the reaction:

H₂  +  I₂   ⇄   2HI

Initially we have 0.001 molesof H₂

and 0.002 moles of I₂

If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.

           H₂     +      I₂      ⇄   2HI

In:     0.001       0.002           -

R:       x                 x                2x

Eq:  0.001-x    0.002-x      0.00187  

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

So in the equilibrium we have:

0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵  moles of H₂

0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂

Expression for Kc is =  (HI)² / (H₂) . (I₂)

0.00187 ² /  6.5×10⁻⁵ . 1.065×10⁻³ = 50.5

5 0
3 years ago
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Then multiply the doses with the available drug. It would be:
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The kinetic energy and the physical state of water depend strongly on the temperature;

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As the temperature increases, the speed of colliding molecules increases and the kinetic energy increases.

  • Secondly, The physical state of water depends on the temperature; water has three states (gas, liquid and solid) depends on the temperature.
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3 years ago
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