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andrew-mc [135]
3 years ago
8

A mixture of Ar, He, and O2 has a total pressure of 1,015 kPa. Argon exerts a partial pressure of 152 kPa and Helium exerts a pa

rtial pressure of 305 kPa. What is the partial pressure of oxygen in this mixture?
a.1,472 kPa
b.558 kPa
c.863 kPa
d.710 kPa
Chemistry
1 answer:
arsen [322]3 years ago
8 0
This one is easy. It's just addition and subtraction. Add the partial pressure of Argon and the partial pressure of Helium:
   152 kPa
<u>+305 kPa</u><u>
</u>  457 kPa

Next, subtract the result from the total pressure:

  1015 kPa
<u>-  457 kPa</u>
   558 kPa
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3 years ago
What are the chemicals used to preserve food and give it color and flavor​
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2 years ago
What type of central-atom orbital hybridization corresponds to each electron-group arrangement:
galina1969 [7]

Tetrahedral arrangement is resulted upon mixing one s and three p atomic orbitals, resulting in 4 hybridized sp^3 orbitals → sp^3 hybridization.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

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3 0
1 year ago
PLEASE HELP WITH ENVI SCI QUESTION
Vladimir79 [104]
Different types of acid deposition are

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3 0
3 years ago
For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici
Brut [27]

<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

             0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)

             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

             -2.3346=\ln (0.124 \gamma)

             e^{-2.3346}=0.124 \gamma

             0.0968=0.124 \gamma

             \gamma=\frac{0.0968}{0.124}=0.78

So, the mean activity coefficient is 0.78.

6 0
3 years ago
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