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andrew-mc [135]
3 years ago
8

A mixture of Ar, He, and O2 has a total pressure of 1,015 kPa. Argon exerts a partial pressure of 152 kPa and Helium exerts a pa

rtial pressure of 305 kPa. What is the partial pressure of oxygen in this mixture?
a.1,472 kPa
b.558 kPa
c.863 kPa
d.710 kPa
Chemistry
1 answer:
arsen [322]3 years ago
8 0
This one is easy. It's just addition and subtraction. Add the partial pressure of Argon and the partial pressure of Helium:
   152 kPa
<u>+305 kPa</u><u>
</u>  457 kPa

Next, subtract the result from the total pressure:

  1015 kPa
<u>-  457 kPa</u>
   558 kPa
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The molarity of the diluted solution is 0.32 M

Considering the question given above, the following data were obtained:

Volume of stock solution (V₁) = 500 mL

Molarity of stock solution (M₁) = 2.1 M

Volume of diluted solution (V₂) = 3.25 L = 3.25 × 1000 = 3250 mL

<h3>Molarity of diluted solution (M₂) =....? </h3>

The molarity of the diluted solution can be obtained as follow:

<h3>M₁V₁ = M₂V₂</h3>

2.1 × 500 = M₂ × 3250

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Therefore, the molarity of the diluted solution is 0.32 M

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Complete Question:

check the first image for complete part of the question

Answer and Explanation:

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(check file 2 attached)

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