First, we find the slope of the given line.
<span>3x − 4y = 7
-4y = -3x + 7
y = (3/4)x - 7/4
The slope of the given line is 3/4.
The slope of the parallel line is also 3/4.
Now we need the equation of the line that has slope 3/4 and passes through point (-4, -2),
We use the point-slope form of the equation of a line.
y - y1 = m(x - x1)
y - (-2) = (3/4)(x - (-4))
y + 2 = (3/4)(x + 4) <---- check option E. Is the fraction 3/4 not there?
y + 2 = (3/4)x + 3
y = (3/4)x + 1
4y = 3x + 4
3x - 4y = -4 <------ this is choice B.
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The value of the derivative at the maximum or minimum for a continuous function must be zero.
<h3>What happens with the derivative at the maximum of minimum?</h3>
So, remember that the derivative at a given value gives the slope of a tangent line to the curve at that point.
Now, also remember that maximums or minimums are points where the behavior of the curve changes (it stops going up and starts going down or things like that).
If you draw the tangent line to these points, you will see that you end with horizontal lines. And the slope of a horizontal line is zero.
So we conclude that the value of the derivative at the maximum or minimum for a continuous function must be zero.
If you want to learn more about maximums and minimums, you can read:
brainly.com/question/24701109
Answer:
The midsegment of a trapezoid is parallel to each base, and its length is one-half the sum of the lengths of the bases.
Step-by-step explanation:
Answer: -9 = a(1 - 3)² + 3
Step-by-step explanation:
Vertex Form Equation:
y = a(x - h)² + k
vertex: (h, k) which means
h = 3
k = 3
because your vertex is (3, 3).
Your point is (1, -9) which is (x, y).
This means
x = 1
y = -9
Now, plug everything into your Vertex Form Equation:
-9 = a(1 - 3)² + 3
That’s your equation and final answer, but of course, if you need to, you can solve for a if you need to.
If a is positive, the parabola opens up. If a is negative, the parabola opens down.
Hope this helps!
