Answer:
m g sin theta = force of object along incline due to gravity
N μ = frictional of incline on object where N is the normal force
N = m g cos theta force perpendicular to incline
m g sin theta = N μ = μ m g cos theta
μ = tan theta = tan 38 = .78
Answer:

Explanation:
As the two charges Q1 and Q2 are placed at some distance apart
so the electric field at mid point will be twice the electric field due to one charge
Because here the two charges are of opposite sign so here the electric field at mid point will be added due to both
so here we have


distance of mid point from one charge is given as



Answer:
The downwind side of an obstacle such as a ridge. The addition of weight on top of a snowpack, usually from precipitation, wind drifting, or a person. An avalanche that releases from a point and spreads downhill collecting more snow - different from a slab avalanche. Also called a point-release or sluff.
Explanation:
Answer:

Explanation:
<u>Net Force</u>
The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.
That acceleration is proportional to the net force and inversely proportional to the mass of the object.
It can be expressed with the formula:

Where
Fn = Net force
m = mass
The m=200 kg crate is pushed horizontally with a force Fa=700 N. The friction force opposes motion and a horizontal net force appears causing the acceleration.
The forces on the vertical direction are in balance since the crate does not accelerate in that direction, thus the weight and the normal force are equal:
N = W = mg
The friction force can be calculated by using the coefficient of friction μ:

Calculating the normal force:
N = 200 * 9.8 = 1,960 N
The friction force is:


The horizontal net force is:


Finally, the acceleration is computed:


Answer: 18.35 m/s
Explanation:
At the highest point of trajectory, the vertical component of the velocity would be zero and the tennis ball would have horizontal component of velocity.
It is given that the initial velocity of the ball is 32 m/s and it makes 35° with the vertical. Hence the horizontal component of the velocity,
v sin θ = 32 m/s × sin 35° = 18.35 m/s
Hence, at the highest point in its trajectory, the tennis ball would be moving with the speed 18.35 m/s.