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Alika [10]
3 years ago
8

Ben and Jerry went for a drive. They decided to stop for a snack and have some ice cream. How fast did they drive on their way t

o the store?
A) 15 km/h
B) 30 km/h
C) 40 km/h
D) 60 km/h

Physics
2 answers:
raketka [301]3 years ago
5 0

Answer: B) 30 km/h

Explanation:

The speed of Ben and Jerry on their way to the store is given by

v=\frac{d}{t}

where

d is the distance they covered

t is the time they took

From the graph, we see that Ben and Jerry travelled for a distance of d=60 km in a time of t=2 h, so their speed is

v=\frac{60 km}{2 h}=30 km/h

wel3 years ago
4 0

Answer:

They are driving at the speed of 30 km/h

Explanation:

From the graph it is clear that,

Total distance covered by Ben and Jerry, d = 60 km

The distance of 60 km is covered in 2 hours.

We have to find how fast they drive on their way to the store i.e their speed. We know that,

speed=\dfrac{distance}{time}

s=\dfrac{60\ km}{2\ h}

s=30\ km/h

Hence, the correct option is (B) " 30 km/h ".

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A coin placed on the cover of a book just begins to move when the cover makes an angle of 38 degrees with the horizontal. What i
RSB [31]

Answer:

m g sin theta = force of object along incline due to gravity

N μ = frictional of incline on object where N is the normal force

N = m g cos theta     force perpendicular to incline

m g sin theta = N μ = μ m g cos theta

μ  = tan theta = tan 38 = .78

6 0
2 years ago
Two charges are in the configuration indicated here. The first charge, Q1 = –1.00 μC, sits at the origin. The second charge, Q2
blagie [28]

Answer:

E_{net} = 3.6 \times 10^4 N/C

Explanation:

As the two charges Q1 and Q2 are placed at some distance apart

so the electric field at mid point will be twice the electric field due to one charge

Because here the two charges are of opposite sign so here the electric field at mid point will be added due to both

so here we have

E_{net} = 2E

E_{net} = 2(\frac{kQ}{r^2})

distance of mid point from one charge is given as

r = \frac{\sqrt{1^2 + 1^2}}{2}

E_{net} = 2 (\frac{(9\times 10^9)(1\times 10^{-6})}{(\frac{1}{\sqrt2})^2}

E_{net} = 3.6 \times 10^4 N/C

5 0
3 years ago
Explain the term "avalanche state"
vagabundo [1.1K]

Answer:

The downwind side of an obstacle such as a ridge. The addition of weight on top of a snowpack, usually from precipitation, wind drifting, or a person. An avalanche that releases from a point and spreads downhill collecting more snow - different from a slab avalanche. Also called a point-release or sluff.

Explanation:

5 0
3 years ago
a 200 kg crate is pushed horizontally with a force of 700 N. If the coefficient of friction is 0.2 calculate the acceleration of
Crazy boy [7]

Answer:

a=1.54\ m/s^2

Explanation:

<u>Net Force</u>

The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.

That acceleration is proportional to the net force and inversely proportional to the mass of the object.

It can be expressed with the formula:

\displaystyle a=\frac{F_n}{m}

Where

Fn = Net force

m  = mass

The m=200 kg crate is pushed horizontally with a force Fa=700 N. The friction force opposes motion and a horizontal net force appears causing the acceleration.

The forces on the vertical direction are in balance since the crate does not accelerate in that direction, thus the weight and the normal force are equal:

N = W = mg

The friction force can be calculated by using the coefficient of friction μ:

F_r=\mu N

Calculating the normal force:

N = 200 * 9.8 = 1,960 N

The friction force is:

F_r=0.2*1,960

F_r=392\ N

The horizontal net force is:

F_n = F_a-F_r=700\ N - 392\ N

F_n = 308\ N

Finally, the acceleration is computed:

\displaystyle a=\frac{308}{200}

\boxed{a=1.54\ m/s^2}

3 0
3 years ago
A player hits a tennis ball in the air with an initial velocity of 32 meters per second at 35 degrees from the vertical how fast
Mamont248 [21]

Answer: 18.35 m/s

Explanation:

At the highest point of trajectory, the vertical component of the velocity would be zero and the tennis ball would have horizontal component of velocity.

It is given that the initial velocity of the ball is 32 m/s and it makes 35° with the vertical. Hence the horizontal component of the velocity,

v sin θ = 32 m/s × sin 35° = 18.35 m/s

Hence, at the highest point in its trajectory, the tennis ball would be moving with the speed  18.35 m/s.

5 0
4 years ago
Read 2 more answers
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