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Scilla [17]
2 years ago
9

An unknown fluid flows at a speed of 31 m/s. Suppose the fluid has a mass of 47 kg runs at this speed. What is the fluid’s kinet

ic energy?
Physics
1 answer:
Leya [2.2K]2 years ago
7 0

Answer:

22583.5J

Explanation:

KE=1/2 mv^2

=1/2*47Kg*(31m/s^2)

=23.5Kg * 961m/s^2

=22583.5J

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A ball bearing of radius of 1.5 mm made of iron of density
Serjik [45]

Answer:

\boxed{\sf Viscosity \ of \ glycerine \ (\eta) = 14.382 \ poise}

Given:

Radius of ball bearing (r) = 1.5 mm = 0.15 cm

Density of iron (ρ) = 7.85 g/cm³

Density of glycerine (σ) = 1.25 g/cm³

Terminal velocity (v) = 2.25 cm/s

Acceleration due to gravity (g) = 980.6 cm/s²

To Find:

Viscosity of glycerine (\sf \eta)

Explanation:

\boxed{ \bold{v =  \frac{2}{9}  \frac{( {r}^{2} ( \rho -  \sigma)g)}{ \eta} }}

\sf \implies \eta =  \frac{2}{9}  \frac{( {r}^{2}( \rho -  \sigma)g )}{v}

Substituting values of r, ρ, σ, v & g in the equation:

\sf \implies \eta =  \frac{2}{9}  \frac{( {(0.15)}^{2}  \times  (7.85 - 1.25) \times 980.6)}{2.25}

\sf \implies \eta =  \frac{2}{9}  \frac{(0.0225 \times 6.6 \times 980.6)}{2.25}

\sf \implies \eta =  \frac{2}{9}  \times  \frac{145.6191}{2.25}

\sf \implies \eta =  \frac{2}{9}  \times 64.7196

\sf \implies \eta =  2 \times 7.191

\sf \implies \eta =  14.382 \: poise

6 0
3 years ago
How does energy acquisition in the deep sea differ from energy acquisition near the ocean’s surface? a. Organisms in the deep se
Montano1993 [528]

that would be the energy from the core. because of the fact that ht eearths core is producing 45mill killawhats and giggawats


3 0
3 years ago
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The radius of Saturn is about 10 times the radius of Venus and the mass is about 100 times that of Venus. How much larger is the
lora16 [44]

let the mass of Venus is M then mass of Saturn is 100 M

similarly if the radius of Venus is R then the radius of Saturn is 10 R

now the force of gravity on a man of mass "m" at the surface of Venus is given by

F_1 = \frac{GMm}{R^2}

now similarly the gravitational force on the man if he is at the surface of Saturn

F_2 = \frac{G*100M*m}{(10R)^2}

F_2 = \frac{GMm}{R^2}

so here if we divide the two forces

\frac{F_1}{F_2} = 1

so here we can say

F1 = F2

so on both planets the gravitational force will be same

7 0
3 years ago
On a hot day, warm air on land rises and collides with cool air. Which of these weather conditions is most likely to follow?
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I think its......C. Hurricane

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Answer:

Well its what makes a salad taste good.

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