What is the turning point of the graph of f(x) = |x| + 4 ?

Machine 1 can complete a task in x hours while an upgraded machine (machine 2) needs 9 fewer hours. The plant manager knows the

lara31 [8.8K]

The (0, 3] is taken out of the picture leaving you with B.

We have given that,

Machine 1 can complete a task in x hours while an upgraded machine (machine 2) needs 9 fewer hours.

We have to determine the,

The plant manager knows the two machines will take at least 6 hours, as represented by the inequality

after you find the intervals.

you also need to consider that the plant manager knows the two machines will take at least 6 hours.

so (0, 3] is taken out of the picture leaving you with B.

To learn more about the inequality visit:

brainly.com/question/24372553

#SPJ1

4 0

2 years ago

The graph shows the functions f(x), p(x), and g(x):

Kruka [31]

Two functions have equal values where their graphs cross.

A) The solution to the pair of equations
.. y = p(x)
.. y = f(x)
will be where the graphs intersect, at (x, y) = (-3, -3).

B) We already know that (-3, -3) is one solution to y=f(x). The graph also appears to go through the point (0, 0).

C) p(x) = g(x) where their graphs cross, at x = -6. Both functions have the value 1 for that value of x.

8 0

3 years ago

call of duty is orginally priced at $70. GameStop gives a discount and Call of Duty is now priced at $64. What is the percentage

Ghella [55]

-8.571428571428571 look up percentage calculator and do it

8 0

3 years ago

Read 2 more answers

Can someone help????

Sonja [21]

Answer:

14 blocks

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100

gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of 660, hence $\mu = 660$ .

The standard deviation is of 90, hence $\sigma = 90$ .

A sample of 100 is taken, hence $n = 100, s = \frac{90}{\sqrt{100}} = 9$ .

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{670 - 660}{9}$

$Z = 1.11$

$Z = 1.11$ has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0

2 years ago