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Greeley [361]
3 years ago
11

712,350 nearest hundred thousand

Mathematics
2 answers:
DENIUS [597]3 years ago
7 0
The answer would be 700,000
soldi70 [24.7K]3 years ago
6 0
1. The number 7 is located in the hundred thousands place

2. Since the number 1 is located in the ten thousands place, it's telling 7 to stay the same

Stays the Same: 1,2,3,4
Goes Up: 5,6,7,8, etc...

712,350 ⇒ 700,000
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What is the distance between (-3,4) and (4,4)​
Licemer1 [7]
(7,0) i think. i’m not sure so check
7 0
3 years ago
Let C(x) be the cost to produce x batches of​ widgets, and let R(x) be the revenue in thousands of dollars. R(x) = − x² + 6x​, C
Musya8 [376]

Answer:

Step-by-step explanation:

Let C(x) be the cost to produce x batches of​ widgets, and let R(x) be the revenue in thousands of dollars.

R(x) = -x^2 + 6x,\\ C(x) = x + 4.

Profit function = Revenue  - cost

So we get profit function by subtracting C(x) from R(x) using algebraic method of subtraction.

Profit function of x

= Pr(x) = R(x) -C(x)\\= -x^2+6x-x-4\\=-x^2+5x-4

7 0
3 years ago
The square is divided into 3 parts.
Lorico [155]
1/3= 5/15
2/5= 6/15

5/15 + 6/15 = 11/15

15/15 - 11/15 = 4/15

Part C= 4/15
4 0
3 years ago
Read 2 more answers
4. A recipe for orange water says, "Mix 3 teaspoons yellow water with 1 teaspoon red water." For this recipe, we might say: "The
notsponge [240]

Answer:

2 batches of orange water = 6 tablespoon of yellow water and 2 tablespoon of red water

4 batches of orange water = 12 tablespoon of yellow water and 4 tablespoon of red water

Step-by-step explanation:

1 batch

Yellow water = 3 teaspoons

Red water = 1 teaspoons

Yellow water : Red water = 3 : 1

2 batches of orange water

Multiply the ratios by 2

Yellow water : Red water

= (3 : 1) * 2

= 6 : 2

2 batches of orange water = 6 tablespoon of yellow water and 2 tablespoon of red water

4 batches of orange water

Multiply the ratios by 4

Yellow water : Red water

= (3 : 1) * 4

= 12 : 4

4 batches of orange water = 12 tablespoon of yellow water and 4 tablespoon of red water

4 0
3 years ago
2.the solution set of x +y =5 and x-y =3
Nataliya [291]

Answer:

Check the solution below

Step-by-step explanation:

2) Given the equation

x +y =5... 1 and

x-y =3 ... 2

Add both equations

x+x = 5+3

2x = 8

x = 8/2

x = 4

Substitute x = 4 into 1:

From 1: x+y = 5

4+y= 5

y = 5-4

y = 1

3) Given

x+3y =15 ... 1

2x+7y=19 .... 2

From 2: x = 15-3y

Substitute into 2

2(15-3y)+7y = 19

30-6y+7y = 19

30+y = 19

y = 19-30

y = -11

Substitute y=-11 into x = 15-3y

x =15-3(-11)

x = 15+33

x = 48

The solution set is (48, -11)

4) given

x/2 +y/3 =0 and x+2y=1

From 1

(3x+2y)/6 = 0

3x+2y = 0.. 3

x+2y= 1... 4

From 4: x = 1-2y

Substutute

3(1-2y) +2y = 0

3-6y+2y = 0

3 -4y = 0

4y = 3

y = 3/4

Since x = 1-2y

x = 1-2(3/4)

x = 1-3/2

x= -1/2

The solution set is (-1/2, 3/4)

5) Given

5.x=1/2 and y =x +1 then solution is

We already know the vkue of x

Get y

y= x+1

y = 1/2 + 1

y = 3/2

Hence the solution set is (1/2, 3/2)

6) Given

3x +y =5 and x -3y =5

From 3; x = 5+3y

Substitute into 1;

3(5+3y)+y = 5

15+9y+y = 5

10y = 5-15

10y =-10

y = -1

Get x;

x = 5+3y

x = 5+3(-1)

x = 5-3

x = 2

Hence two solution set is (2,-1)

6 0
3 years ago
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