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umka2103 [35]
3 years ago
15

Place the following numbers in order from least to greatest.

Mathematics
2 answers:
PIT_PIT [208]3 years ago
7 0

The answer is D put all those numbers into fractions and make them have the same denominator.
const2013 [10]3 years ago
4 0

Answer: Your answer is D

Step-by-step explanation:

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Im not sure how to do this or what function to use SIN, COS, or TAN but if you could walk me through it that would be so so so a
Elanso [62]

Answer: 3.8

Step-by-step explanation:first, you need to figure out what side you’re looking for. Side AC is opposite of the angle you’re given. They also give you length of side AB which is 4. That is the hypotenuse (side directly across from right angle). So, you have the hypotenuse, and need the find the opposite side measure. Which option uses opposite and hypotenuse? That’s Sin. So, you would do: sin70 = ? / 4.

sin (of given angle)= opposite / hypotenuse.

Sin (70 degrees) = ? / 4

Then you solve for “?”

Type sin70 into your calculator, then multiply both sides by 4 to get “?” by itself. You should get 3.758770483, which rounds to 3.8

5 0
2 years ago
If I dozen people get on a train and five of them get off at the next stop how many of those people are left on train
Vinil7 [7]
A dozen people is 12. 5 people get off.

12 - 5 = 7
3 0
3 years ago
Read 2 more answers
On a math test a​ student, Sarah​, has to identify all the coefficients and constants of the expression 8m+2+n. Sarah says that
Shalnov [3]

Answer:

Coefficients: 8

Constants: 2

Variables: m and n

Step-by-step explanation:

Sarah had made no errors-

A number on its own is called a Constant.

A coefficient is a number used to multiply a variable.

6 0
3 years ago
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The measure of one of the acute angles in a right triangle is given. what is the measure of the other angle?
yuradex [85]
This is your favourite answer

5 0
2 years ago
Please help: linear algebra problem. (Linear combinations)
DochEvi [55]

Answer:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

This tells us that:

A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]

b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right].

So we want to find a way to express this as:

Ax=b where x is the scalar vector, \left[\begin{array}{ccc}c\\d\end{array}\right].

So we can write this as:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

3 0
3 years ago
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