Original APR = 10.22% compounded monthly.
Original effective interest rate, compounded monthly
= (1+(0.1022/12))^12
= 1.10712576
Original effective interest rate, compounded daily
= (1+(0.1022/365)^365
= 1.107589126
Difference in rate due to compounding periods
= 1.107589126 - 1.10712576
= 0.00046336
= 0.04634%
Answer: -6
Step-by-step explanation:
From the question, Elsa pumped 18 gallons of water out of her pool and this was done over a period of 3 minutes at a constant rate. Since it is done at a content rate, to get the change in the amount of water in the pool each minute, we divide 18 gallons by 3. This can be written mathematically as:
= 18 gallons ÷ 3
= 6 gallons
Change = -6
The change in the amount of water in the pool each minute will be -6gallons hope this helps
Answer:
because it can go overseas
Answer:
No. When all you want to do is estimate a population parameter, you should construct a confidence interval.
Step-by-step explanation:
In this case, there is no other prior estimation about the population to test (a hypothesis to nullify). The only thing you can do is construct a confidence interval of the proportion, where the standard deviation can be calculated in function of the proportion and the sample size.
The right answer is E: "No. When all you want to do is estimate a population parameter, you should construct a confidence interval."
Answer:
640 m
Step-by-step explanation:
We can consider 4 seconds to be 1 time unit. Then 8 more seconds is 2 more time units, for a total of 3 time units.
The distance is proportional to the square of the number of time units. After 1 time unit, the distance is 1² × 80 m. Then after 3 time units, the distance will be 3² × 80 m = 720 m.
In the additional 2 time units (8 seconds), the ball dropped an additional
... (720 -80) m = 640 m
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<em>Alternate solution</em>
You can write the equation for the proportionality and find the constant that goes into it. If we use seconds (not 4-second intervals) as the time unit, then we can say ...
... d = kt²
Filling in the information related to the first 4 seconds, we have ...
... 80 = k(4)²
... 80/16 = k = 5
Then the distance equation becomes ...
... d = 5t²
After 12 seconds (the first 4 plus the next 8), the distance will be ...
... d = 5×12² = 5×144 = 720 . . . meters
That is, the ball dropped an additional 720 -80 = 640 meters in the 12 -4 = 8 seconds after the first data point.
