Isotopes of any given factor all incorporate the equal variety of protons, so they have the identical atomic wide variety (for example, the atomic wide variety of helium is usually 2). Isotopes of a given factor include exceptional numbers of neutrons, therefore, special isotopes have special mass numbers.
The pOH scale is similar to the pH scale in that a pOH of 7 is indicative of a neutral solution. A basic solution has a pOH less than 7, while an acidic solution has a pOH of greater than 7
<h3>What is
pOH scale?</h3>
Based on the relative concentration of hydrogen and hydroxyl ions, the pH and pOH scales are used primarily in chemistry, biology, and soil science to describe and measure the acidity and basicity of neutral, acidic, and basic solutions in water.
The terms pH and pOH scale are frequently used and crucial for determining the chemical, biological, and soil health by converting the values of hydrogen or hydroxyl ion concentrations or by utilizing pH paper and meters.
The pH scale or chart, which measures the concentration of hydrogen and hydroxyl ions in acidic and alkaline solutions, was initially developed by Sorensen.
To learn more about pOH scale from the given link:
brainly.com/question/16631843
#SPJ4
Sodium phosphide is the inorganic compound with the formula Na3P.
Answer:
The amount of heat that is released is -925.2 cal
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is the amount of heat that a body can receive or release without affecting its molecular structure, that is, it does not change the state (solid, liquid, gaseous). In other words, sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state.
The equation that allows to calculate heat exchanges is:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.
In this case:
- c= 1
- m= 25.7 g
- ΔT= Tfinal - Tinitial= 49 °C - 85 °C= -36 °C
Replacing:
Q= 1 *25.7 g* (-36 C)
Solving:
Q= -925.2 cal
<u><em>The amount of heat that is released is -925.2 cal</em></u>
