Answer:
Explanation:
Hello there!
In this case, it possible to use the Rydberg equation in order to calculate the wavelength for this transition from n=3 to n=2 as shown below:
Thus, we plug in the corresponding energy levels and the Rydberg constant to obtain:
Best regards!
This reaction does not exist since all of the reactants and products are aqueous.
Lithium has charge of +1 and bromide has charge of - 1. So they combine to form the compound lithium bromide which is expressed as LiBr.
<h3><u>Explanation:</u></h3>
Lithium is an alkali metal placed in group 1 or periodic table. It has a valency of 1 which is achieved as lithium loses an electron to achieve a charge of +1.
Bromine is a halogen which is placed in group 17 of periodic table. It has a valency of 1 which is achieved as bromine looses an election to achieve a charge of - 1.
Lithium is the cation and bromide is the anion. So lithium is written in front and bromine following the cation. And as both of their valencies are 1, so they form the compound LiBr.
Ion knoe Wdym by “be able to describ’ so ima put it in my own words idr lol:)
if you talm bout some kentic energy or sum ok but other Dan dat ion knoe tbh
I can explain how transferring kinetic energy in and out of a substance can cause a change
