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saul85 [17]
3 years ago
15

Metals are both good heat conductors and good electrical conductors because of the

Physics
2 answers:
Yuliya22 [10]3 years ago
5 0

Answer:

looseness of outer electrons in metal atoms

Explanation:

Unlike in insulators the valance electrons in metals are free to roam inside the boundaries of the metal slab. These electrons are called free electrons.

These electrons are free to move because there is no gab between their valance band and conduction band.

Since they are free to move they can transfer charges easily and be a good conductor.

Also heat exchange takes place when one electron collides with another moving electron or a stationary atom.

This is why metals are both good heat conductors and good electrical conductors.

Lostsunrise [7]3 years ago
4 0
<h2>Answer:</h2>

<em>Metals are both good heat conductors and good electrical conductors because of the </em><em>looseness of outer electrons in metal atoms</em>

_________________________

Unlike nonmetals that are insulators, most metals are both good heat conductors and good electrical conductors. This is because within a solid metal there is one or more outer electrons in each atom that become detached and can move freely through the solid metal, but <em>what about the other electrons?</em>  Well, the y remain bound to the positively charged nuclei, and bound within the material in almost fixed positions. On the other hand, insulators are material having few, very few or no electrons that are allowed to move freely through  the material.

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An object moving at a velocity of 32 m/s slows to a stop in 4 seconds. What was its acceleration
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Answer:

8

Explanation:

Because you divide 32/4 which gives you 8.

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3 years ago
Why is electric current scalar quantity with having direction ?​
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Explanation:

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What is dark energy?
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4 0
3 years ago
A block, M1=10kg, slides down a smooth, curved incline of height 5m. It collides elastically with another block, M2=5kg, which i
erma4kov [3.2K]

Answer:

2.86 m

Explanation:

Given:

M₁ = 10 kg

M₂ = 5 kg

\mu_k = 0.5

height, h = 5 m

distance traveled, s = 2 m

spring constant, k = 250 N/m

now,

the initial velocity of the first block as it approaches the second block

u₁ = √(2 × g × h)

or

u₁ = √(2 × 9.8 × 5)

or

u₁ = 9.89 m/s

let the velocity of second ball be v₂

now from the conservation of momentum, we have

M₁ × u₁ = M₂ × v₂

on substituting the values, we get

10 × 9.89 = 5 × v₂

or

v₂ = 19.79 m/s

now,

let the velocity of mass 2 when it reaches the spring be v₃

from the work energy theorem,  we have

Work done by the friction force = change in kinetic energy of the mass 2

or

0.5\times5\times9.8\times2 = \frac{1}{2}\times5\times( v_3^2-19.79^2)

or

v₃ = 20.27 m/s

now, let the spring is compressed by the distance 'x'

therefore, from the conservation of energy

we have

Energy of the spring =  Kinetic energy of the mass 2

or

\frac{1}{2}kx^2=\frac{1}{2}mv_3^2

on substituting the values, we get

\frac{1}{2}\times250\times x^2=\frac{1}{2}\times5\times20.27^2

or

x = 2.86 m

8 0
3 years ago
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