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saul85 [17]
3 years ago
15

Metals are both good heat conductors and good electrical conductors because of the

Physics
2 answers:
Yuliya22 [10]3 years ago
5 0

Answer:

looseness of outer electrons in metal atoms

Explanation:

Unlike in insulators the valance electrons in metals are free to roam inside the boundaries of the metal slab. These electrons are called free electrons.

These electrons are free to move because there is no gab between their valance band and conduction band.

Since they are free to move they can transfer charges easily and be a good conductor.

Also heat exchange takes place when one electron collides with another moving electron or a stationary atom.

This is why metals are both good heat conductors and good electrical conductors.

Lostsunrise [7]3 years ago
4 0
<h2>Answer:</h2>

<em>Metals are both good heat conductors and good electrical conductors because of the </em><em>looseness of outer electrons in metal atoms</em>

_________________________

Unlike nonmetals that are insulators, most metals are both good heat conductors and good electrical conductors. This is because within a solid metal there is one or more outer electrons in each atom that become detached and can move freely through the solid metal, but <em>what about the other electrons?</em>  Well, the y remain bound to the positively charged nuclei, and bound within the material in almost fixed positions. On the other hand, insulators are material having few, very few or no electrons that are allowed to move freely through  the material.

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2 years ago
As water across the surface of the earth it dissolves material as it travels. What property of water does this demonstrate?
iris [78.8K]

Answer:

B) Water is a solvent

Explanation:

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3 0
3 years ago
A radio have a wavelength of 0.3m and travels at a speed of 300,000,000 m/s. What is the frequency of this wave?​
Ilya [14]

The frequency of the wave is 1\cdot 10^9 Hz

Explanation:

The frequency, the wavelength and the speed of a wave are related by the following equation:

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\lambda is the wavelength

For the radio wave in this problem,

\lambda = 0.3 m

c=300,000,000 m/s = 3\cdot 10^8 m/s

Therefore, the frequency is:

f=\frac{c}{\lambda}=\frac{3\cdot 10^8}{0.3}=1\cdot 10^9 Hz

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Answer:

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Explanation:

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3 years ago
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