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Licemer1 [7]
3 years ago
15

Mountain Airlines has annual operating revenues of less than $75 million with hubs in Denver and Salt Lake City. This airline wo

uld be classified in which air carrier category?
Physics
1 answer:
Vladimir79 [104]3 years ago
5 0

Answer:

Regional carrier                  

Explanation:

Like in many countries, in United States, the airlines are either privately owned or publicly owned. In the United States, airlines are categorized in to major airline carriers, national airline carriers and regional airline carriers by the revenue it generates.

Accordingly, if an airline generates revenue more than 1 billion dollar in a year, it falls in the Major Airline carriers category.

It the revenue generated by the airline is within the range of $100 million to $1 billion, then it is called National airline carriers.

However, if the revenue is less than 100 million dollar for a year, then that airline is called a Regional airline carrier.

In the context, as the revenue generated by the Mountain Airlines is less than  75 million dollar, it is called Regional carrier.

Hence, the answer is --- Regional carrier                  

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The patellar tendon attaches to the tibia at a 20 deg angle 3 cm from the axis of rotation at the knee. If the force generated i
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Answer:

the resulting angular acceleration is 15.65 rad/s²

Explanation:

Given the data in the question;

force generated in the patellar tendon F = 400 N

patellar tendon attaches to the tibia at a 20° angle 3 cm( 0.03 m ) from the axis of rotation at the knee.

so Torque produced by the knee will be;

T = F × d⊥

T = 400 N × 0.03 m × sin( 20° )

T = 400 N × 0.03 m × 0.342

T = 4.104 N.m

Now, we determine the moment of inertia of the knee

I = mk²

given that; the lower leg and foot have a combined mass of 4.2kg and a given radius of gyration of 25 cm ( 0.25 m )

we substitute

I = 4.2 kg × ( 0.25 m )²

I = 4.2 kg × 0.0626 m²

I = 0.2625 kg.m²

So from the relation of Moment of inertia, Torque and angular acceleration;

T = I∝

we make angular acceleration ∝, subject of the formula

∝ = T / I

we substitute

∝ = 4.104 / 0.2625

∝ = 15.65 rad/s²

Therefore, the resulting angular acceleration is 15.65 rad/s²

8 0
3 years ago
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fgiga [73]

Answer:

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Explanation:

6 0
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kifflom [539]

Answer: Option D: 5.5×10²Joules

Explanation:

Work done is the product of applied force and displacement of the object in the direction of force.

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It is given that the force applied is, F = 55 N

The displacement in the direction of force, s = 10 m

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Thus, work done on the object:

W = 55 N × 10 m × cos 0° = 550 J = 5.5 × 10² J

Hence, the correct option is D.

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