Explanation:
This question does not indicate the options to choose from, so I'll just outline the factors that determine if the nautical speed is safe for your boat.
When travelling with your boat, or just cruising around on your boat, It is necessary to consider the following factors before deciding if the speed you're travelling with is safe. These factors are:
1. <u>The weather and marine conditions</u>: One should calculate for the wind speed and direction, the water current, and the general condition of the water body.
2. <u>The traffic density on the water at that instance</u>: You should be mindful of other vessels on the water body before choosing your safe speed. The area available, and the proximity of these vessels to your boat should be considered
3. <u>Visibility</u>: The degree of visibility is a very important factor when determining what speed is safe for you. The speed should be chosen such that there is enough room and time to easily maneuver in order to prevent collision with an obstacle. Visibility can be impaired by fog, mist and cloudiness.
4. <u>The responsiveness of your vessels</u>: The ease with which your vessel responds to sudden change in direction should be considered. You shouldn't travel at a high speed if your boat is slow to respond to being maneuvered.
5. <u>Other navigational hazards</u>: Other navigational facilities and their proximity like buoys should be accounted for when choosing your vehicle speed.
Other factors includes:
draft of the vessel, limitations of radar equipment, and the wake your vehicle will leave at this speed.
From these listed factors, I think you should be able to pick out your answer.
Answer:
Isothermal expansion W₁ =-37198.9 J
Polytropic Compression W₂ =-34872.82 J
Isobaric Compression W₃ = -6974.566 J
The net work for the cycle = -79046.29 J
Explanation:
Mass of air = 0.15 kg = 150 g
Molar mass = 28.9647 g/mol
Number of moles = 150 g /28.9647 g/mol = 5.179 moles of air
PV = nRT therefrore V = nRT/(P) = 5.179*8.314*(350+273.15)/(2×10⁶) = 0.0134167 m³
For isothermal expansion we have
P₁V₁ = P₂V₂ or V₂ = P₁V₁/P₂ = 2×10⁶*0.0134167 / (5×10⁵) = 0.0536668 m³
Therefore work done
W₁ = -nRTln(V₂/V₁) = -26833ln(4) = -37198.9 J
Stage 2
Compression polytropically we have
where P₃ = 2 MPa
Therefore V₃ = = 1.6904×10⁻² m³
Work = W₂ = = -34872.82 J
or T₃ = = 785.12 K
Isobaric compression we have thus
Work done W₃ = P(V₁ -V₃) = -6974.566 J
Total work = W₁ + W₂ + W₃ = -37198.9 J + -34872.82 J + -6974.566 J = -79046.29 J
Answer is TRUE.
a person must maintain an ongoing awareness and capacity to divide their attention between the vehicle's operation, position, speed, the condition of the roadway, and the actions of other drivers.
Answer:
The lamp will remain off.
Explanation:
I assume this is a simple series circuit with a battery, a switch, an incandescent lamp and a capacitor.
Since the circuit is of continuous current (because it uses a battery), after the switch has remained closed for a long time the capacitor will be fully charged. Being fully charged, no continuous current will flow through the capacitor, and since it is in series with the rest of the circuit there will be no current anywhere, so the lamp will remain off.