Answer:
Use cases are known to be a set of instruction or processes between a User/Actor with the system to produce a desired input.
With the aid of a diagram, the set of use cases that are carried out in this ATM are given below:
Insert PIN
(1)Perform required transaction
(2)Withdrawal
(3)Deposit
(4)Transfer
(5)Change PIN
(6)Exit
Note: Kindly find an attached diagram of the Use case as part of the solution to process carried out at the ATM
Sources: The diagram of the Use case for ATM was researched and taken from Quizlet.
Explanation:
Solution
Use cases are normally a set of instruction or processes between a User/Actor with the system to produce a desired input.
A use case diagram or image is a graphical representation of all the use case or processes that connects or interact with the system
The use case diagram is a part of Unified Modelling Language also called the UML.
The set of use cases that are carried out in this ATM use case diagram to know the requirements of the ATM is shown below:
Now both the customer/client and Bank are seen as Actors.
Actors are the ones or people that interface with the system.
Answer:
The air pressure in the tank is 53.9
Solution:
As per the question:
Discharge rate, Q = 20 litres/ sec =
(Since, 1 litre = )
Diameter of the bore, d = 6 cm = 0.06 m
Head loss due to friction,
Height,
Now,
The velocity in the bore is given by:
Now, using Bernoulli's eqn:
(1)
The velocity head is given by:
Now, by using energy conservation on the surface of water on the roof and that in the tank :
Answer:
Velocity of 5 cm diameter pipe is 1.38 m/s
Explanation:
Use following equation of Relation between the Reynolds numbers of both pipes
=
=
= Reynold number of water pipe
= Reynold number of oil pipe
= Velocity of water 5 diameter pipe = ?
= Velocity of oil 12 diameter pipe = 2.30
= Kinetic Viscosity of water = 1 x
/s
= Kinetic Viscosity of oil = 4 x
/s
= Diameter of pipe used for water = 0.05 m
= Diameter of pipe used for oil = 0.12 m
Use the formula
=
By Removing square rots on both sides
=
=
x
= [ (0.23 x 0.12m ) / (4 x
/s) x 0.05 ] 1 x
/s
= 1.38 m/s