7. Which equation below represents a vertical line? y = x – 0 y = x + 0 y = 4 x = 4

Mathematics

1 answer:

prisoha [69]3 years ago

6 0

x=4 would be a vertical line

You might be interested in

How can complex fractions be used to solve involving ratios

Alex777 [14]

Bring them to the same denominator and solve for x

8 0

3 years ago

Andy and Christopher are measuring a liquid solution using graduated cylinders, Andy uses 3.5 liters of the liquid solution, and

Gre4nikov [31]

Answer:

$Ratio = 0.74$

Step-by-step explanation:

Represent

- Andy with A

- Christopher with C

$A = 3.5L$

$C = 2580mL$

Required

Determine the ratio of C to A

Ratio is represented as thus:

$Ratio = C:A$

Rewrite as fraction

$Ratio = \frac{C}{A}$

This gives

$Ratio = \frac{2580mL}{3.5L}$

Convert L to mL

$Ratio = \frac{2580mL}{3.5*1000mL}$

$Ratio = \frac{2580mL}{3500mL}$

$Ratio = \frac{2580}{3500}$

$Ratio = 0.73714285714$

$Ratio = 0.74$ --- Approximated

6 0

3 years ago

Will someone help with this ! I was allowed a retry for it and I don’t know how to do it

pashok25 [27]

Answer:

$\frac{dN}{dt}=k(725-N)\\separating the variables and integrating\\\int \frac{dN}{725-N}=\int kdt+c\\-log (725-N)=kt+c\\log (725-N)=-kt-c\\(725-N)=e^{-kt-c} =e^{-kt} *e^{-c} =Ce^{-kt} \\when t=0,N=400\\725-400=Ce^{0} =C\\C=325\\when t=3,N=650\\725-650=325e^{-3k} \\\frac{75}{325}=(e^{-k})^3\\\\e^{-k} =(\frac{3}{13}) ^{\frac{1}{3} } \\when t=5\\725-N=325(\frac{3}{13}) ^{\frac{5}{3} } =325*\frac{3}{13}*(\frac{3}{13} )^{\frac{2}{3}}\\N=725-75*(\frac{3}{13} )^{\frac{2}{3} }=725-28=697$