Answer:
7 reservoirs
Step-by-step explanation:
1 yards = 3 feet => 3.5 yards = 10.5 feet
To determine how many numbers of reservoirs to reserve 90000, we first need to determine the capacity of each reservoirs (how much liquid one reservoir can contain) - which is equal to the volume.
The formula to calculate the volume of a circular cylinder is:
- <em>Volume of cylinder = Area of base x Height </em>
<em />
The base of this cylinder is a circle with radius equal to 4 feet. (
)
=> The are of the base is = 
= 3.14 x 4^2 = 50.24 feet square
=> The volume of cylinder = Area of base x Height
=> The volume of one cylinder = 50.24 x 10.5 = 527.52 Cubic foot
We have: 1 cubic foot = 28.317 liters
=> 1 liter = 1/28.317 cubic foot
=> 90000 liters equal to: 90000/28.317 = 3,178.303 cubic foot
The number of reservoirs needed to contain 90000 liters of liquid is:
3,178.303/527.52 = 6.025
=> So that it needs 7 reservoirs to store all 90000 liters of liquid.
<span>4. Simplify the expression.
sine of x to the second power minus one divided by cosine of negative x</span>
<span>(1−sin2(x))/(sin(x)−csc(x))<span>
</span>sin2x+cos2x=1</span>
<span>1−sin2x=cos2x<span>
</span>cos2(x)/(sin(x)−csc(x))</span>
<span>csc(x)=1/sin(x)</span>
<span>cos2(x)/(sin(x)− 1/sin(x))= cos2(x)/((sin2(x)− 1)/sin(x))</span>
<span>sin2(x)− 1=-cos2(x)</span>
<span>cos2(x)/(( -cos2(x))/sin(x))
=-sin(x)</span>
<span>
the answer is the letter a)
-sin x
</span><span>
5. Find all solutions in the interval [0, 2π). (6 points)sin2x + sin x = 0</span> using a graphical tool
the solutions
x1=0
x2=pi
<span>x3=3pi/2
the answer is the letter </span><span>
D) x = 0, π, three pi divided by two</span>
Given:
The radius of the sphere is 6 in.
To find:
The volume of the sphere.
Solution:
We know that, the volume of a sphere is
Where, r is the radius of the sphere.
Putting r=6, we get
The volume of the sphere is 904.78 inches cubed.
Therefore, the correct option is C.
Answer:
Option D graph
Step-by-step explanation:
x - 4 ≥ - 1
add 4 to both sides, x - 4 + 4 ≥ - 1 + 4
x ≥ 3
so x is greater than or equal to 3
- equal to means closed dot at 3
- greater than means arrow to the right of 3
