So, x > 7 - 2; x >5 or
4 - x > 6; 4 - x - 6 > 0;
4 - 6 -x > 0;
- 2 -x > 0;
-2 > x;
Finally, x > 5 or x < -2;
Answer:
-2/3
Step-by-step explanation:
The slope of a line can be represented as 
where (x1, y1) and (x2, y2) are points on the line. We can substitute the points given, (-3, 5) and (6, -1), to calculate the slope:
Answer:
Step-by-step explanation:
1) Given figure is a parallelogram
Area = 144 cm²
base * altitude = 144
16 * x = 144
x =144/16
x = 9 cm
2)2) Trapezium
Area = 
; {a and b are parallel sides of trapezium}
( 37 +27 /2) * x = 480 cm²
64/2 * h = 480
32 * h = 480
h = 480/32
h = 15 cm
<span>v = 45 km/hr
u = 72 km/hr
Can't sketch the graph, but can describe it.
The Y-axis will be the distance. At the origin it will be 0, and at the highest point it will have the value of 120. The X-axis will be time in minutes. At the origin it will be 0 and at the rightmost point, it will be 160. The graph will consist of 3 line segments. They are
1. A segment from (0,0) to (80,60)
2. A segment from (80,60) to (110,60)
3. A segment from (110,60) to (160,120)
The motorist originally intended on driving for 2 2/3 hours to travel 120 km. So divide the distance by the time to get the original intended speed.
120 km / 8/3 = 120 km * 3/8 = 360/8 = 45 km/hr
After traveling for 80 minutes (half of the original time allowed), the motorist should be half of the way to the destination, or 120/2 = 60km. Let's verify that.
45 * 4/3 = 180/3 = 60 km.
So we have a good cross check that our initial speed was correct. v = 45 km/hr
Now having spent 30 minutes fixing the problem, out motorist now has 160-80-30 = 50 minutes available to travel 60 km. So let's divide the distance by time:
60 / 5/6 = 60 * 6/5 = 360/5 = 72 km/hr
So the 2nd leg of the trip was at a speed of 72 km/hr</span>
