In comparison they both show feeding relationship in an ecosystem.
In contrast, a food chain is a simple linear feeding relationship while a food web is a complex feeding relationship.
2) The arrows is to show the direction of the feeding relationship
Answer:
It discusses Pollution levels in the Air
Explanation: Air can be hazardous to those lungs that are weak. They have something called an Air Quality Alert to warn those with weak lungs to take precautions. Hope this helped!
Answer:
cytosol (intracellular fluid), interstitial fluid, plasma
RNA and DNA-RNA hybrids are more dense than simply DNA if the density of different nucleic acids is tested using a CsCl gradient.
The primary technique employed in molecular biology is the extraction of DNA, RNA, and protein. Scientists can separate materials according to size, shape, and density by using density gradient centrifugation. Isopycnic centrifugation, a sort of density gradient centrifugation that Meselson and Stahl developed, employed a cesium chloride solution to separate DNA molecules solely on the basis of density. Because DNA has hydrogen bonds between its strands, which makes it less dense than RNA, RNA has a far larger density than DNA. RNA can be obtained at the test tube's bottom using a CsCl density gradient and high centrifugation, whereas DNA can be recovered in the middle layer.
To learn more about nucleic acids click here brainly.com/question/11309892
#SPJ4
Answer:
A. Glucose:
As lactose is absent will follow the glucose metabolism, so the lac repressor will hold tightly with the operator which leads to the prevention of transcription as RNA polymerase can not bind to promoter so no lactose metabolism.
B. lactose:
In the case or wild mutant lactose metabolism will occur as lactose is present, allolactose binds to the lac repressor thus the operator and promoter are free so transcription starts. The same result will be in all test except in the case of a mutant repressor.
C. glucose and lactose:
In this case, diauxic growth will occur. This growth takes place when two sugars are present in the media. The preferred sugar will be consumed first That is glucose. Then a lag phase will come which will be followed by the second sugar metabolism that is lactose. the given two cases :
Lactose will be metabolized first, as operator site mutation prevents repressor protein binding and thus will lead to the constitutive synthesis of lac operon in test B.
The same thing will happen, as in this case also, constitutive synthesis of lac operon will happen in test C.
Cultures grown in the presence of both glucose and lactose are metabolizing lactose. In the test (b) and (c) will be responsible due to constitutive synthesis of lac operon will happen.
