IV. Molasses will sink because it has a greater density. The rest will float or suspend.
Answer:
CaCl2
And
potasium phosphate is a general name for salt of potassium and phosphate ions . The compounds can exist as
K3PO4 (Tripotassium phosphate)
K2HPO4 (di potassium phosphate)
KH2PO4 (mono potassium phosphate)
Explanation:
Calcium chloride salt is an ionic compound. so it contains both cations and anions. That means it has a positively charged ion and a negatively charged ion. In an ionic compound their is a transfer of electron. The valence electron or the charge ion present in an atom can be use to predict the chemical formula of this compound . Base on the compound the positive end is calcium while the negative end is chlorine .
Ca2+ and Cl-
cross multiply the charges
CaCl2
The charge of phosphate ions are (PO4)3−, (HPO4)2− and (H2PO4)−. And base on the valence electron potassium has a stable charge of +1 (K+). The phosphate ion produces the negative charge when it reacts with potassium.
If potassium goes into reaction with any of the phosphate ion it will be as follows.
K+ and (PO4)3−
cross multiply the charge as usual
K3PO4(tripotassium phosphate)
K+ and (HPO4)2−
cross multiply the charge as usual
K2HPO4(di potassium phosphate)
K+ and (H2PO4)−
cross multiply the charge as usual
KH2PO4 (mono potassium phosphate)
Answer:
Cr
Explanation:
Cr will displace Sn from compound because Cr is higher than Sn in the electrochemical series of metals
Answer:
Wavelength of sound waves millimetres
Explanation:
The speed of any wave is equal to the product of its wavelength and frequency.
This can be represented mathematically as
Where
V is the speed of sound waves
f is the frequency of sound waves
and
is the wavelength of the sound waves.
Substituting the given values in above equation we get -
meters
millimetres
Answer:
The limiting reacting is O2
Explanation:
Step 1: data given
Number of moles O2 = 21 moles
Number of moles C6H6O = 4.0 moles
Step 2: The balanced equation
C6H6O + 7O2 → 6CO2 + 3H2O
Step 3: Calculate the limiting reactant
For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O
O2 is the limiting reactant. It will completely be consumed (21 moles).
C6H6O is in excess.
For 7 moles O2 we need 1 mol C6H6O
For 21 moles O2 we'll need 21/7 = 3 moles C6H6O
There will remain 4.0 - 3.0 = 1 mol C6H6O
Step 4: calculate products
For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O
For 21 moles O2 we'll have 6/7 * 21 = 18 moles CO2
For 21 moles O2 we'll have 3/7 * 21 = 9 moles H2O
The limiting reacting is O2