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kompoz [17]
3 years ago
5

How many CO2 molecules in 0.0189 mol of CO2?

Chemistry
1 answer:
Blizzard [7]3 years ago
4 0

Answer:

option C is correct = 1.14 × 10²² molecules of  CO₂

Explanation:

Given data:

Number of moles of CO₂ = 0.0189 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

For given question:

1 mole of CO₂ =  6.022 × 10²³ molecules of  CO₂

0.0189 mol of CO₂ ×  6.022 × 10²³ molecules of  CO₂ / 1mol

1.14 × 10²² molecules of  CO₂

Thus, option C is correct.

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Carbon dioxide and helium which has a higher van der waals force of attraction between molecules ​
raketka [301]

Answer:

Carbon dioxide  

Explanation:

Neither helium nor carbon dioxide has a molecular dipole, so their strongest van der Waals attractive forces are London forces.

Helium is a small spherical atom with only a two electrons, so its atoms have quite weak attractions to each other.

CO₂ is a large linear molecule. It has more electrons than helium, so the attractive forces are greater. Furthermore, the molecules can align themselves compactly side-by-side and maximize the attractions (see below).

For example. CO₂ becomes a solid at -78 °C, but helium must be cooled to -272 °C to make it freeze (that's just 1 °C above absolute zero).

7 0
3 years ago
What is the percent concentration of a 250 ml solution with 0.120 g nacl?
Effectus [21]
0.048 percent is the answer
3 0
3 years ago
A photon has 8.0 × 10–15 J of energy. Planck’s constant is 6.63 × 10–34 J•s. What is the frequency of the photon
german
The formula is:
frequency * h (Planck's constant) = Energy
So, to find frequency you need just divide energy by the constant:
frequency = (8 * 10^-15 J) / (6.63 * 10^-34 J*s) = 1.2 * 10^19 1/s or 1.2 * 10^19 Hz
5 0
3 years ago
Read 2 more answers
What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?
kompoz [17]

Answer: 0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of Al(OH)_3 = 0.610 g

Molar mass of Al(OH)_3 = 78 g/mol

\text{Number of moles}=\frac{0.610g}{78g/mol}

Number of moles of Al(OH)_3 = 0.0078 moles

The reaction between Al(OH)_3 and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O

By Stoichiometry,

1 mole of  Al(OH)_3 reacts with 3 moles of HCl

So, 0.0078 moles of Al(OH)_3 will react with \frac{3}{1}\times 0.0078 = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

0.0234moles=\frac{\text{Given mass}}{36.5g/mol}

Mass of HCl required will be = 0.8541 grams

3 0
3 years ago
a compound has an empirical formula of C6H6NO. what is its molar formula, if its molar mass is 216.2 g/mol
Pavlova-9 [17]

Answer: C12H12N2O2

Explanation:

6 0
3 years ago
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