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TiliK225 [7]
3 years ago
9

The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kj . f the change in e

nthalpy is -5074.3 kj , how much work is done during the combustion
Chemistry
1 answer:
TEA [102]3 years ago
6 0

<u>Given:</u>

Change in internal energy = ΔU = -5084.1 kJ

Change in enthalpy = ΔH = -5074.3 kJ

<u>To determine:</u>

The work done, W

<u>Explanation:</u>

Based on the first law of thermodynamics,

ΔH = ΔU + PΔV

the work done by a gas is given as:

W = -PΔV

Therefore:

ΔH = ΔU - W

W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ

Ans: Work done is -9.8 kJ


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Explanation:

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Explanation:

∵ no. of moles (n) = mass / molar mass.

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Answer:

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On the products side, there are 2 Na molecules and 2 Cl molecules

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