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Whitepunk [10]
3 years ago
6

How much heat is required to increase the temperature of 198.5 grams of water from 25.0

Chemistry
1 answer:
velikii [3]3 years ago
4 0

5.27*10^4 (52,700.)

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A naturally occurring oil co-distills with water to produce an oil/water distillate that is 20% oil by weight. If the molecular
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Answer:

Explanation:

Partial pressure of oil = mole fraction of oil x total pressure

mole fraction of oil = mole of oil / mole of water + mole of oil

= mole of oil = mass of oil / molecular weight of oil

= 20 / 100 = .2

mole of water = 80 / 18

= 4.444

mole fraction of oil =  .2 / .2 + 4.444

= .2 / 4.644

Partial pressure of oil = mole fraction of oil x total pressure

= (.2 / 4.644 ) x 760 mm

= 32.73 mm Hg .

3 0
3 years ago
Convert 45 kL to mL (must show work)​
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Answer:

1 kiloliter = 1,000,000 milliliters

45 × 1,000,000

45 KL = 45,000,000 ML

8 0
2 years ago
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Part A: You are given a beaker containing a solution of an enzyme that hydrolyzes adenosine triphosphate (ATP) while it generate
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Answer:

1) magnesium chloride

2) b) The copper is getting oxidized from Cu+ to Cu2+ and turns blue.

Explanation:

The work published by David N. Frick, Sukalyani Banik, and Ryan S. Rypma in J Mol Biol. 2007 Jan 26; 365(4): 1017–1032 clearly shows that divalent metal ions of group 2 such as Mg^2+ play an important role in ATP hydrolysis. Addition of EDTA decreased the rate of hydrolysis of ATP (due to sequestration of the divalent ion of group 2) indicating an active participation of divalent ions in the process.

2) The copper I ion is colourless because it is a d^10 specie. However, when it is oxidized to Cu^2+, a blue colour appears in the solution.

4 0
2 years ago
Which type of bond is formed between atoms of solid gold
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Answer:

covalent bonds

Explanation:

5 0
3 years ago
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A sample of pure tin metal is dissolved in nitric acid to produce 15.00 mL of solution containing Sn2+. When this tin solution i
Rudik [331]

Answer:

1.00 M

Explanation:

Sn^2+ reacts with KMNO4 as follows;

5Sn^2+(aq) + 2MnO4^-(aq) + 16H^+(aq) ----> 5Sn^4+(aq) + 2Mn^+(aq) + 8H2O(l)

The number of moles of MnO4^- reacted = 42.1/1000 L × 0.145 mol/L

= 0.0061 moles

If 5 moles of Sn^2+ reacts with 2 moles of MnO4^-

x moles of Sn^2+ reacts with 0.0061 moles of MnO4^-

x= 5 × 0.0061/2

x= 0.015 moles

Since the volume of the Sn^2+ solution is 15.00mL or 0.015 L

number of moles = concentration × volume

Concentration = number of moles/volume

Concentration= 0.015 moles/0.015 L

Concentration = 1 M

6 0
3 years ago
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