If Ka for HCN is 6. 2×10^−10 at 25 °C, then the value of Kb for cn− at 25 °C is 1.6 × 10^(-5).
<h3>What is base dissociation constant? </h3><h3 />
The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.
The dissociation reaction of hydrogen cyanide can be given as
HCN --- (H+) + (CN-)
Given,
The value of Ka for HCN is 6.2× 10^(-10)
The correlation between base dissociation constant and acid dissociation constant is
Kw = Ka × Kb
Kw = 10^(-14)
Substituting values of Ka and Kw,
Kb = 10^(-14) /{6.2×10^(-10) }
= 1.6× 10^(-5)
Thus, the value of base dissociation constant at 25°C is 1.6 × 10^(-5).
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Answer:
The molecule has a bent geometry
Explanation:
Let us look again at the principles of VSEPR theory. The shape of a molecule depends on the number of electron pairs that surround the valence shell of the central atom in the molecule.
Lone pairs distort the molecular geometry away from what is expected on the basis of VSEPR theory.
The molecule described in the question has the form AEX2. Two substituents and one lone pair form three electron domains around the central atom. The expected geometry is trigonal planar but the observed molecular geometry is bent because of the lone pairs present.
Answer:
C) 1.3 mol
Explanation:
Using gas law we can find the initial moles of the sample of the mixture, as follows:
PV = nRT
PV / RT = n
<em>Where P is pressure: 4.0atm</em>
<em>V is volume: 9.6L</em>
<em>R is gas constant: 0.082atmL/molK</em>
<em>T is absolute temperature: 300K</em>
<em>And n are moles of the gas</em>
<em />
PV / RT = n
4.0atm*9.6L / 0.082atmL/molK300K = n
n = 1.56moles of the mixture of the gas are present into the 9.6L container
Now, 14% of this gas is hydrogen that was removed of the system, that is:
1.56mol*14% = 0.22 moles of hydrogen are removed.
Thus, moles of gas that remains in the container are:
1.56mol - 0.22mol = 1.34mol.
Right answer is:
<h3>C) 1.3 mol</h3>
I woud say B because jupiter has more of a gravitational pull
